Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
Answer: Option
Explanation:
A's 2 day's work = | ![]() |
1 | x 2 | ![]() |
= | 1 | . |
20 | 10 |
(A + B + C)'s 1 day's work = | ![]() |
1 | + | 1 | + | 1 | ![]() |
= | 6 | = | 1 | . |
20 | 30 | 60 | 60 | 10 |
Work done in 3 days = | ![]() |
1 | + | 1 | ![]() |
= | 1 | . |
10 | 10 | 5 |
Now, | 1 | work is done in 3 days. |
5 |
Whole work will be done in (3 x 5) = 15 days.
Discussion:
357 comments Page 29 of 36.
Manish Raj said:
7 years ago
A's work = 20,
A+B+C = 10,
Together {A+(A+B+C)}/2 = (30+20)/2 = 15.
A+B+C = 10,
Together {A+(A+B+C)}/2 = (30+20)/2 = 15.
Lavanya said:
7 years ago
The total work done for three days means. There should be 1/10+1/10+1/10 should come right. Why they used it for 2 days only?
Md Toufique said:
7 years ago
Let us suppose total work to be done is 60 unit, then A, B and C's one day work is 3, 2, 1 respectively,
Then in every 3 days they will finish 12 unit of work (3, 3, 6),
Then, 12 + 12 + 12 + 12+ 12 =60 work done so total days = 3+3+3+3+3=15.
Then in every 3 days they will finish 12 unit of work (3, 3, 6),
Then, 12 + 12 + 12 + 12+ 12 =60 work done so total days = 3+3+3+3+3=15.
Rishi said:
7 years ago
How can you say the total work is 1?
Sha said:
7 years ago
How does the last step is (3*5=15)?
How come 3 here?
How come 3 here?
Dipankar said:
7 years ago
12-60.
1-5,
So 3=5*3=15.
1-5,
So 3=5*3=15.
Prem K said:
7 years ago
A's 1 day's work is 1/20.
A's 3 day's work is 3/20.
(B+C)'s 1 day's work is 1/30+1/60 = 1/20.
B and C will work on every third day means A will work three days and B and C will work for 1 day.
(A+B+C)'s 3 day's work = A's 3 day's work + (B+C)'s 1 day's work,
= 3/20 + 1/20,
= 1/5.
3 day's work is 1/5 then, whole work will be done in (3*5) = 15 days.
A's 3 day's work is 3/20.
(B+C)'s 1 day's work is 1/30+1/60 = 1/20.
B and C will work on every third day means A will work three days and B and C will work for 1 day.
(A+B+C)'s 3 day's work = A's 3 day's work + (B+C)'s 1 day's work,
= 3/20 + 1/20,
= 1/5.
3 day's work is 1/5 then, whole work will be done in (3*5) = 15 days.
Gayatri Dhokne said:
7 years ago
Take the LCM of A, B, C which is 60.
For LCM we have to multiply A, B, C by 3,2,1 respectively, this is work done per day by each of them.
For the first 2 days, only A works so, 2*3=6.
On the 3rd day A is assisted by B&C so,total work done in one day is 6units,
Therefore, the work they have done in 3days is 6+6=12,
Total work is done =60.
Days require to complete the work by A,B, C =60 ÷ 12=5days.
Days required by A to complete work = 5*3 = 15days.
For LCM we have to multiply A, B, C by 3,2,1 respectively, this is work done per day by each of them.
For the first 2 days, only A works so, 2*3=6.
On the 3rd day A is assisted by B&C so,total work done in one day is 6units,
Therefore, the work they have done in 3days is 6+6=12,
Total work is done =60.
Days require to complete the work by A,B, C =60 ÷ 12=5days.
Days required by A to complete work = 5*3 = 15days.
Sravya Suryadevara said:
7 years ago
Here in question, it is mentioned that A alone worked for 2 days, on the third day B and C assisted him.
So,
A's 2 days work= 2(1/20) = 1/10.
On third day three together worked.
i.e.,
3rd day work = (1/20)+(1/30)+(1/60) = 1/10.
Work done in 3 days= (1/10)+(1/10) = 1/5.
Total work is 3*5 = 15 days.
So,
A's 2 days work= 2(1/20) = 1/10.
On third day three together worked.
i.e.,
3rd day work = (1/20)+(1/30)+(1/60) = 1/10.
Work done in 3 days= (1/10)+(1/10) = 1/5.
Total work is 3*5 = 15 days.
Ajaykumarchevuri said:
7 years ago
A-20days
B-30days.
C-60days
LCM is 60
So,
A one day work 3 units (20*3)
B one day work 2 units(30*2)
C one day work 1 unit (1*60)
Then; 6 units ( both A+B+C one day work on every third day)
So A 2 days work = 3units *2 = 6 units
A+B+C on 3 Rd day = 6 units*1= 6 units
So, weget 12 units.
So 12/60 = 1/5 (A 2 days work +(A+B+C) work on a third day/total work)
So 3days * 1/5 = 15 days.
Here the answer.
B-30days.
C-60days
LCM is 60
So,
A one day work 3 units (20*3)
B one day work 2 units(30*2)
C one day work 1 unit (1*60)
Then; 6 units ( both A+B+C one day work on every third day)
So A 2 days work = 3units *2 = 6 units
A+B+C on 3 Rd day = 6 units*1= 6 units
So, weget 12 units.
So 12/60 = 1/5 (A 2 days work +(A+B+C) work on a third day/total work)
So 3days * 1/5 = 15 days.
Here the answer.
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