Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
12 days
15 days
16 days
18 days
Answer: Option
Explanation:

A's 2 day's work = 1 x 2 = 1 .
20 10

(A + B + C)'s 1 day's work = 1 + 1 +1 = 6 = 1 .
20 30 60 60 10

Work done in 3 days = 1 + 1 = 1 .
10 10 5

Now, 1 work is done in 3 days.
5

Whole work will be done in (3 x 5) = 15 days.

Discussion:
357 comments Page 27 of 36.

Sarathy said:   9 years ago
A's total work = 1.
A's 1 day work = 1/20 = 0.05.
B's 1 day work = 1/30 = 0.03.
c's 1 day work = 1/60 = 0.01.

B + C combined work together = 0.03 + 0.01 = 0.04.
A's 3 day work = 0.05 + 0.05 + 0.05 + 0.04 = 0.19.
If answer is 15 means = 5 * (0.19) = 0.95 remaining 0.05.

So, the answer is wrong.
In 16th day = (15days work + A's one day work).
= (0.95 + 0.05),
= 1.

So, 16 days is the correct answer.

Puspanjalisahoo said:   9 years ago
I am not understanding A's 2 day's work. Please explain.

Priya said:   9 years ago
@All.

Please explain the last step.

Rudra said:   9 years ago
Here, first of all, we have to find the total work.
So for this, L.C.M of 20 30 60 = 60,
a's b's c's one day work =3 2 1 (one day work)
Now a's 2days work = 6.
b's, c,s one day's woks = 2.
+1= 3.
So three days work 3 + 3 + 3 + 3 = 12.
3 days = 12
3*5 =15 days, 12 * 5 = 60.

Anand J said:   9 years ago
I'm finding difficulty in understanding the question. How to analyze the question? Please help me out.

Mohammed said:   9 years ago
Why here they take 2?

Vikash said:   9 years ago
Here first we take LCM of 20,30,60 that is 60.
After that , A work done = 60/20 = 3
Similar, B =60/30 = 2 and C = 60/60 = 1.

According to questions, A is assisted by B and C on every 3rd day.
i.e : 3 persons are Working.

Total work = A + A +(A + B + C) (Here a ,B and come together on every third day).
Total work = 3 + 3 + (3 + 2 + 1) = 12.

Now work = 60 is divided by 12 rem is 0.
Means 60/12 = 5 . We got 5 and 3 persons are working.
So that, 5 *3 = 15 days.

Aiswarya said:   9 years ago
How did we get that 1/10+1/10 ? Can anyone help me?

PRASHANT HATWAR said:   9 years ago
Here A's 2 days work = 1/20 * 2 = 1/10,
And every third day A, B and C working together,
Means A, B, C's 1 day work is A + B + C = 1/20 + 1/30 + 1/60 = 3 + 2 + 1/60 = 6/60 = 1/10
So here complete 3 days work is 1/10 + 1/10 = 2/10 =1/5.
It means 1/5 work done in 3 days.
So work remains is 1 - 1/5 = 4/5.

So here,
1/5 : 4/5 :: 3 : x
1/5 * x = 4/5 * 3
x =12.

It means 4/5 work done in 12 days,
so complete work done in,
12 + 3 = 15days.

Therefore, the answer in 15.

Rah said:   9 years ago
Suppose B and C are helping a, = b 1/30 + c 1/60 + a 1/20.

But B and C are helping only on third day so( b+c / 3)+a = (1/30+1/60 =3/60 = 1/20/3=1/60)+ 1/20= 1/20+1/60=4/60=1/15 = 15.


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