Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 3)
3.
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
12 days
15 days
16 days
18 days
Answer: Option
Explanation:

A's 2 day's work = 1 x 2 = 1 .
20 10

(A + B + C)'s 1 day's work = 1 + 1 +1 = 6 = 1 .
20 30 60 60 10

Work done in 3 days = 1 + 1 = 1 .
10 10 5

Now, 1 work is done in 3 days.
5

Whole work will be done in (3 x 5) = 15 days.

Discussion:
357 comments Page 21 of 36.

Sudhansu sekhar said:   10 years ago
Why applied 1/10 + 1/10?

Shridhar said:   9 years ago
A as done the work for 2 days, he is asserted to B and C in 3rd, he as not done the work at 3rd day. Then why 1/20 + 1/30 + 1/60?

Shridhar said:   9 years ago
Got it on 3 day B & C is helping A.

Ompal. said:   9 years ago
A, B, and C person can a do work 20, 40 and 60 days respectivily. When they works alternative. They compeleted work how many days.

Shruthi said:   9 years ago
Please explain the 2nd step => (A + B + C) 's 1 day's work.

How it becomes 6/60.

Jemish said:   9 years ago
My new approach to explaining the answer.

=> A is working continuously.
=> B and C join at every 3rd day.

A's efficiency is used as it is,

But B and C's efficiency is used 1/3rd part considering a task.

thus,
A--> 1/20
B--> 1/3 * (1/30)
c--> 1/3 * (1/60)

Now simple.

To find out days required = 1/20 + 1/90 + 1/180 = 1/15.

Answer: 15 days required.

Jenni said:   9 years ago
How to multiply and solve this equation?

1/20 + 1/30 + 1/60

Preethu said:   9 years ago
Why do we multiply it by 5?

How we get the answer as 15? Please help me.

Aariz said:   9 years ago
Hey, guys. I have some confusion in this question. Is there anyone from Delhi, please guide me to solve this question.

Rayhan said:   9 years ago
Good explanation. I really understand this. Thankyou all.


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