Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 27)
27.
A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in:
Answer: Option
Explanation:
| (B + C)'s 1 day's work = |  |
1 | + | 1 |  |
= | 7 | . |
| 9 | 12 | 36 |
| Work done by B and C in 3 days = | |
7 | x 3 | |
= | 7 | . |
| 36 | 12 |
| Remaining work = | |
1 - | 7 | |
= | 5 | . |
| 12 | 12 |
| Now, | 1 | work is done by A in 1 day. |
| 24 |
| So, | 5 | work is done by A in | |
24 x | 5 | |
= 10 days. |
| 12 | 12 |
Discussion:
17 comments Page 2 of 2.
Renuka said:
1 decade ago
1-7/12 = 12-7/12 = 5/12.
Kezang said:
1 decade ago
1-7/12 = 5/12, please explain.
ANGEL said:
1 decade ago
(a+b+c) 's 1 day work = 1/24+1/9+1/12=17/72.
So 3 day work = 17/72*3 = 17/24.
Remaining work = 1-17/24 = 724.
1/24 work done by a in 1 day.
7/24 work done in 24*7/24 = 7.
= 7+3 = 10.
So 3 day work = 17/72*3 = 17/24.
Remaining work = 1-17/24 = 724.
1/24 work done by a in 1 day.
7/24 work done in 24*7/24 = 7.
= 7+3 = 10.
Rakesh said:
1 decade ago
1/24 work is done by A in 1 day. How this step comes can give clear explanation?
Shiva said:
1 decade ago
b+c can cmplte in 12/7 days
24-(7*24/12)
=10days
24-(7*24/12)
=10days
Snehagoud said:
1 decade ago
What is short method for finding the LCM of three numbers please?
Rajender said:
2 decades ago
Are you imaging that 1 day work pending after work done by (b + c) for 3 days
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