Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 20)
20.
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
Answer: Option
Explanation:
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
5 : 4 :: 20 : x  x = |
 |
4 x 20 |  |
| 5 |
x = 16 days.
Hence, Tanya takes 16 days to complete the work.
Discussion:
94 comments Page 5 of 10.
Patrick said:
8 years ago
Sakshi efficiency = 100/20 = 5;
Tanya = 5 x 1.25 = 6.25;
The number of days taken by Tanya to do the same piece of work is: 100/6.25 = 16 days.
Tanya = 5 x 1.25 = 6.25;
The number of days taken by Tanya to do the same piece of work is: 100/6.25 = 16 days.
Jigme Wangchuk said:
5 years ago
Anyone explain the correct answer.
Komal Singh said:
7 years ago
@Sakshi.
If takes 125 times to complete her work in 20 days, Tanya takes 100.
Therefore if we cross multiply to find how much days will Tanya take to complete work.
i.e 125/100*20/? we get 16!
If takes 125 times to complete her work in 20 days, Tanya takes 100.
Therefore if we cross multiply to find how much days will Tanya take to complete work.
i.e 125/100*20/? we get 16!
Divyansh said:
7 years ago
I am not getting it how 16?
Let's think this way Sakshi take 20 days which is 240 hours.
25% of 240 = 60.
240 - 60 = 180.
and 180 hours = 15days.
Please can anyone help me.
Let's think this way Sakshi take 20 days which is 240 hours.
25% of 240 = 60.
240 - 60 = 180.
and 180 hours = 15days.
Please can anyone help me.
Sufiyan Ansari said:
7 years ago
See This for those Who do Time and work with LCM..
It is said that Sakshi can do a piece of work in 20 days with her efficiency so we cannot take 25%of 20.
Here it is given 25% more efficient.
So efficiency of Sakhsi : Tanya.
Assume: S:T = 100unit : 125 unit (25%more).
Therefore ,
Total work = 100unit x 20days.
:. Tanya would do the same work in:
Total work/ Tanya efficiency,
:. 100unit x 20/125= 16 days.
It is said that Sakshi can do a piece of work in 20 days with her efficiency so we cannot take 25%of 20.
Here it is given 25% more efficient.
So efficiency of Sakhsi : Tanya.
Assume: S:T = 100unit : 125 unit (25%more).
Therefore ,
Total work = 100unit x 20days.
:. Tanya would do the same work in:
Total work/ Tanya efficiency,
:. 100unit x 20/125= 16 days.
Srilatha said:
7 years ago
Sakshi complete the work in 20 days . Tanya is 25% more efficient means;
in 20days 25%=5 days.
it means t complete the work in 5 days earlier.
so 20-5=15 answer.
Then how it comes as 16?
in 20days 25%=5 days.
it means t complete the work in 5 days earlier.
so 20-5=15 answer.
Then how it comes as 16?
Pitambar said:
7 years ago
A certain number of men do a piece of work in 10 days, if there are 10 men less, it will take 10 days more to finish the work. How many men were there originally. Can anyone solve this to find a solution?
Kajal said:
6 years ago
Here (125% of 1/20)=1/16 that means in 16 days.
Samar said:
1 decade ago
20*0.25=5
subtract 5 from 20
20-5=15Ans
I also get the answer 15
I did not understand how the answer is 16.
subtract 5 from 20
20-5=15Ans
I also get the answer 15
I did not understand how the answer is 16.
Roji said:
1 decade ago
Hi friends,
Why can't we do in this manner?
Sakshi can done in 20 days i.e.,100%.
Where as, Tanya is x days i.e., 125%.
By cross multiplication,
x = (125*20)/100 = 25.
Answer we get 25.
So, am I wrong?
Already this type of process done in 17th sum but here it is not working yar.
Why can't we do in this manner?
Sakshi can done in 20 days i.e.,100%.
Where as, Tanya is x days i.e., 125%.
By cross multiplication,
x = (125*20)/100 = 25.
Answer we get 25.
So, am I wrong?
Already this type of process done in 17th sum but here it is not working yar.
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