Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 20)
20.
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
Answer: Option
Explanation:
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
5 : 4 :: 20 : x  x = |
 |
4 x 20 |  |
| 5 |
x = 16 days.
Hence, Tanya takes 16 days to complete the work.
Discussion:
94 comments Page 4 of 10.
Epsilon said:
8 years ago
Sakshi does 1 unit in =20Days.
Tanya does (1+1/4)=5/4 unit in = 20Days.
So, Tanya does one unit in=20*4/5 = 16 days,
I think efficiency here is related to the amount of work done.
Tanya does (1+1/4)=5/4 unit in = 20Days.
So, Tanya does one unit in=20*4/5 = 16 days,
I think efficiency here is related to the amount of work done.
Shadab Akhtar said:
9 years ago
Sakshi = 1/20 (given).
Tanya = (125/100) * Sakshi (Tanya is 25% more efficient than Sakshi).
Tanya= (125/100) * 1/20.
= 1/16.
Hence, Tanya does the same piece of work in 16 days.
Tanya = (125/100) * Sakshi (Tanya is 25% more efficient than Sakshi).
Tanya= (125/100) * 1/20.
= 1/16.
Hence, Tanya does the same piece of work in 16 days.
Jitendra said:
1 decade ago
Let Sakshi completes the whole work = 100 days.
Then Tanya will complete it = 75 days.
Now, 100 = 20.
1 = 20/100 = 1/5.
75 = (1/5) *75 = 15 days.
So answer should be 15 days.
Then Tanya will complete it = 75 days.
Now, 100 = 20.
1 = 20/100 = 1/5.
75 = (1/5) *75 = 15 days.
So answer should be 15 days.
Akram said:
1 decade ago
x:y::p:q.
Product of mean = product of extreme.
..i.e.. y*p = x*q.
y*p/x*q = 1.
Same way : 5:4::20:x
4*20/5 = x
4*4 = x
x = 16.
Product of mean = product of extreme.
..i.e.. y*p = x*q.
y*p/x*q = 1.
Same way : 5:4::20:x
4*20/5 = x
4*4 = x
x = 16.
Mithun said:
8 years ago
[Tanya effective than sakshi [20days] , hence answer should be less than 20days]
Sakshi 125--------->20
Tanya 100-------->?
[cross multiply]
20 x 100 / 125 =16days.
Sakshi 125--------->20
Tanya 100-------->?
[cross multiply]
20 x 100 / 125 =16days.
Divyansh said:
7 years ago
I am not getting it how 16?
Let's think this way Sakshi take 20 days which is 240 hours.
25% of 240 = 60.
240 - 60 = 180.
and 180 hours = 15days.
Please can anyone help me.
Let's think this way Sakshi take 20 days which is 240 hours.
25% of 240 = 60.
240 - 60 = 180.
and 180 hours = 15days.
Please can anyone help me.
Priya said:
1 decade ago
Nothing to do all this just simple calculation in question it is given Tanya is 25% more efficient than Sakshi which do in 20 days.
So Tanya will do 125/100*1/20 = 4 days.
So Tanya will do 125/100*1/20 = 4 days.
Suresh KS said:
9 years ago
Hi friends I agree your answer is 16 based on your methods.
So please let me know how many days Tanya takes if she is 50% more efficient than sakshi based on your methods.
So please let me know how many days Tanya takes if she is 50% more efficient than sakshi based on your methods.
Ashwini said:
9 years ago
According to me, it should be;
Tanya is 25% efficient than Sakshi so that means she finishes work taking 25% less time.
So, 20 - 25 * 20, then finally we get 15 days.
Tanya is 25% efficient than Sakshi so that means she finishes work taking 25% less time.
So, 20 - 25 * 20, then finally we get 15 days.
Pavan said:
1 decade ago
Here question starts with sakshi so we must take s=100.
Then 25% eff so T=75.
Then the ratio we get is 3:4.
Answer will be 15.
How can it be 16.
Can anyone please?
Then 25% eff so T=75.
Then the ratio we get is 3:4.
Answer will be 15.
How can it be 16.
Can anyone please?
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