Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 20)
20.
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
Answer: Option
Explanation:
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
5 : 4 :: 20 : x  x = |
 |
4 x 20 |  |
| 5 |
x = 16 days.
Hence, Tanya takes 16 days to complete the work.
Discussion:
94 comments Page 3 of 10.
Pitambar said:
7 years ago
A certain number of men do a piece of work in 10 days, if there are 10 men less, it will take 10 days more to finish the work. How many men were there originally. Can anyone solve this to find a solution?
Shawisk said:
1 decade ago
Read carefully
for tanya & sakshi, the actual ratio is 100:75=4:3
bcz if tanya do same work complete @ 100% in x days
then sakshi can complete only 75% of that work in x days
so keep it in mind
for tanya & sakshi, the actual ratio is 100:75=4:3
bcz if tanya do same work complete @ 100% in x days
then sakshi can complete only 75% of that work in x days
so keep it in mind
San said:
1 decade ago
Efficiency is : (1/Number of total days to complete a work).
So, efficiency of sakshy = 1/20.
And,efficiency of Tanya = 1/20 + 25% of (1/20).
Which is,
1/16.
So, Tanya will complete in 16 days.
So, efficiency of sakshy = 1/20.
And,efficiency of Tanya = 1/20 + 25% of (1/20).
Which is,
1/16.
So, Tanya will complete in 16 days.
Sanjay said:
8 years ago
Tanya 1 day =100 unit (make).
Sakshi 1 day =75 unit.
Sakshi 20 days = 1500 unit make ( so this is total work ).
Then tanya make = 1500 / 100 = 15 days.
15 days 1500 unit.
15 --> Can Be Answer.
Sakshi 1 day =75 unit.
Sakshi 20 days = 1500 unit make ( so this is total work ).
Then tanya make = 1500 / 100 = 15 days.
15 days 1500 unit.
15 --> Can Be Answer.
Komal Singh said:
7 years ago
@Sakshi.
If takes 125 times to complete her work in 20 days, Tanya takes 100.
Therefore if we cross multiply to find how much days will Tanya take to complete work.
i.e 125/100*20/? we get 16!
If takes 125 times to complete her work in 20 days, Tanya takes 100.
Therefore if we cross multiply to find how much days will Tanya take to complete work.
i.e 125/100*20/? we get 16!
Sonu jangra said:
10 years ago
Sakshi do 1 day's the work = 1/20.
Now, Tanya do the work 25% more efficient than Sakshi = 1/20*25/100 = 1/80.
So, Tanya will do the total work = 1/20+1/80 = 5/80 = 1/16.
So 1*16/1 = 16 days.
Now, Tanya do the work 25% more efficient than Sakshi = 1/20*25/100 = 1/80.
So, Tanya will do the total work = 1/20+1/80 = 5/80 = 1/16.
So 1*16/1 = 16 days.
Anshu said:
1 decade ago
Hey,
You can understand it like this.
As we know working efficiency of sakshi is 1/20.
And working efficiency of tanya is 25% greater.
So tanya eff = 1/20*(125/100)=1/16.
Hence time 16 days.
You can understand it like this.
As we know working efficiency of sakshi is 1/20.
And working efficiency of tanya is 25% greater.
So tanya eff = 1/20*(125/100)=1/16.
Hence time 16 days.
Srilatha said:
7 years ago
Sakshi complete the work in 20 days . Tanya is 25% more efficient means;
in 20days 25%=5 days.
it means t complete the work in 5 days earlier.
so 20-5=15 answer.
Then how it comes as 16?
in 20days 25%=5 days.
it means t complete the work in 5 days earlier.
so 20-5=15 answer.
Then how it comes as 16?
Atul said:
8 years ago
Sakshi cannot be taken as 125, as Sakshi is the reference point here, she must be taken as 100.
So, Tanya becomes 75 (25% more efficient).
Then the ratio becomes 4:3 instated of 5:4.
So, Tanya becomes 75 (25% more efficient).
Then the ratio becomes 4:3 instated of 5:4.
Sanjoy said:
1 decade ago
100T = 125S, 20S = 1, consider x day required for Tania.
4T = 5S, S = 1/20, Tx =1.
4T = 5*1/20 1/16x = 1.
4T = 1/4 x = 16.
T = 1/16.
So Tania required 16days to complete the work.
4T = 5S, S = 1/20, Tx =1.
4T = 5*1/20 1/16x = 1.
4T = 1/4 x = 16.
T = 1/16.
So Tania required 16days to complete the work.
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