Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 20)
20.
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
Answer: Option
Explanation:
Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.
Suppose Tanya takes x days to do the work.
5 : 4 :: 20 : x  x = |
 |
4 x 20 |  |
| 5 |
x = 16 days.
Hence, Tanya takes 16 days to complete the work.
Discussion:
94 comments Page 3 of 10.
Srilatha said:
7 years ago
Sakshi complete the work in 20 days . Tanya is 25% more efficient means;
in 20days 25%=5 days.
it means t complete the work in 5 days earlier.
so 20-5=15 answer.
Then how it comes as 16?
in 20days 25%=5 days.
it means t complete the work in 5 days earlier.
so 20-5=15 answer.
Then how it comes as 16?
Vishal Bhadikar said:
7 years ago
Why not 15 days? Explain..
100%=20 day.
25%=x day.
X = 5 days.
Now take efficient that we need to subtract 20-5 = 15 days.
Explain to me if I am wrong.
100%=20 day.
25%=x day.
X = 5 days.
Now take efficient that we need to subtract 20-5 = 15 days.
Explain to me if I am wrong.
(2)
Sufiyan Ansari said:
7 years ago
See This for those Who do Time and work with LCM..
It is said that Sakshi can do a piece of work in 20 days with her efficiency so we cannot take 25%of 20.
Here it is given 25% more efficient.
So efficiency of Sakhsi : Tanya.
Assume: S:T = 100unit : 125 unit (25%more).
Therefore ,
Total work = 100unit x 20days.
:. Tanya would do the same work in:
Total work/ Tanya efficiency,
:. 100unit x 20/125= 16 days.
It is said that Sakshi can do a piece of work in 20 days with her efficiency so we cannot take 25%of 20.
Here it is given 25% more efficient.
So efficiency of Sakhsi : Tanya.
Assume: S:T = 100unit : 125 unit (25%more).
Therefore ,
Total work = 100unit x 20days.
:. Tanya would do the same work in:
Total work/ Tanya efficiency,
:. 100unit x 20/125= 16 days.
Divyansh said:
7 years ago
I am not getting it how 16?
Let's think this way Sakshi take 20 days which is 240 hours.
25% of 240 = 60.
240 - 60 = 180.
and 180 hours = 15days.
Please can anyone help me.
Let's think this way Sakshi take 20 days which is 240 hours.
25% of 240 = 60.
240 - 60 = 180.
and 180 hours = 15days.
Please can anyone help me.
Komal Singh said:
7 years ago
@Sakshi.
If takes 125 times to complete her work in 20 days, Tanya takes 100.
Therefore if we cross multiply to find how much days will Tanya take to complete work.
i.e 125/100*20/? we get 16!
If takes 125 times to complete her work in 20 days, Tanya takes 100.
Therefore if we cross multiply to find how much days will Tanya take to complete work.
i.e 125/100*20/? we get 16!
Manish Niroti said:
8 years ago
Tanya & sakshi capacity =5:4.
Tanya & Sakshi time taken=4:5.
If Sakshi taking 20 days it means 5 is representing 20 so 20/5 =4,
and multiply 4 with taken by Tanya so you will get 4*4 =16.
Ratio and proportion concept.
Tanya & Sakshi time taken=4:5.
If Sakshi taking 20 days it means 5 is representing 20 so 20/5 =4,
and multiply 4 with taken by Tanya so you will get 4*4 =16.
Ratio and proportion concept.
(1)
Patrick said:
8 years ago
Sakshi efficiency = 100/20 = 5;
Tanya = 5 x 1.25 = 6.25;
The number of days taken by Tanya to do the same piece of work is: 100/6.25 = 16 days.
Tanya = 5 x 1.25 = 6.25;
The number of days taken by Tanya to do the same piece of work is: 100/6.25 = 16 days.
Mahesh Neupane said:
8 years ago
Sakshi efficiency is 1/20.
Tanya Efficiency is 25% more than Sakshi.
So, 1/20+(25%of1/20)=16%.
Tanya Efficiency is 25% more than Sakshi.
So, 1/20+(25%of1/20)=16%.
Sahithikarne said:
8 years ago
25% of 20 is 5 then the answer is 20-5=15. But how it is 16?
Atul said:
8 years ago
Sakshi cannot be taken as 125, as Sakshi is the reference point here, she must be taken as 100.
So, Tanya becomes 75 (25% more efficient).
Then the ratio becomes 4:3 instated of 5:4.
So, Tanya becomes 75 (25% more efficient).
Then the ratio becomes 4:3 instated of 5:4.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers