Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 8)
8.
A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:
Answer: Option
Explanation:
(A + B)'s 1 day's work = | 1 |
10 |
C's 1 day's work = | 1 |
50 |
(A + B + C)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 6 | = | 3 | . .... (i) |
10 | 50 | 50 | 25 |
A's 1 day's work = (B + C)'s 1 day's work .... (ii)
From (i) and (ii), we get: 2 x (A's 1 day's work) = | 3 |
25 |
![]() |
3 | . |
50 |
![]() |
![]() |
1 | - | 3 | ![]() |
= | 2 | = | 1 | . |
10 | 50 | 50 | 25 |
So, B alone could do the work in 25 days.
Discussion:
146 comments Page 14 of 15.
Rajni Saini said:
1 decade ago
Awoke u r grreaatt dear.thnx a lot.
Deepak said:
9 years ago
@Nagu, nice explanation. Thank you.
Amit Gaikwad said:
6 years ago
@Saurabh.
Thanks for the solution.
Thanks for the solution.
Kinnari said:
1 decade ago
I like your method Mr. Awoke. :)
Sowmya said:
1 decade ago
@awoke.
Your method is awesome.
Your method is awesome.
Deepika said:
10 years ago
By adding a+b+c i.e. 1/10+1/50.
Ayesha said:
9 years ago
Your shortcut is great @Awoke.
Ranganayaki said:
8 years ago
Thank you for explaining this.
Gaurav said:
7 years ago
Good, thanks @Shivangi Sharma.
Jagan said:
6 years ago
Awesome method thanks @Awoke.
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