Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 8)
8.
A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:
Answer: Option
Explanation:
| (A + B)'s 1 day's work = | 1 |
| 10 |
| C's 1 day's work = | 1 |
| 50 |
| (A + B + C)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 6 | = | 3 | . .... (i) |
| 10 | 50 | 50 | 25 |
A's 1 day's work = (B + C)'s 1 day's work .... (ii)
| From (i) and (ii), we get: 2 x (A's 1 day's work) = | 3 |
| 25 |
A's 1 day's work = |
3 | . |
| 50 |
B's 1 day's work |
![]() |
1 | - | 3 | ![]() |
= | 2 | = | 1 | . |
| 10 | 50 | 50 | 25 |
So, B alone could do the work in 25 days.
Discussion:
147 comments Page 13 of 15.
Ganesh said:
1 decade ago
How you got 6/50?
Please someone explain.
Please someone explain.
Naheed said:
6 years ago
Thank you @Awoke your method was so easy.
Thilak said:
5 years ago
How come 1/10, Can you please explain it?
Sumedha said:
1 decade ago
@Awoke.
Your short cut method is great.
Your short cut method is great.
Pratiksha said:
1 decade ago
Thanku sneha I getting your explanation.
Dinesh said:
1 decade ago
@AWOKE.
I liked your method. Thank you.
I liked your method. Thank you.
Suganya said:
2 decades ago
How you get that 2*(A's 1day work)=3/25
Vinoth said:
2 decades ago
How u got x (A's 1 day's work) = 3/25
Shweta said:
6 years ago
Thank you @Awoke your method was easy.
Ravi said:
4 years ago
Thanks @Sneha.
You explained it well.
You explained it well.
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A's 1 day's work =
B's 1 day's work