Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 15)
15.
A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
Answer: Option
Explanation:
Let distance = x km and usual rate = y kmph.
| Then, | x | - | x | = | 40 |  2y(y + 3) = 9x ....(i) |
| y | y + 3 | 60 |
| And, | x | - | x | = | 40 | y(y - 2) = 3x ....(ii) |
| y -2 | y | 60 |
On dividing (i) by (ii), we get: x = 40.
Discussion:
121 comments Page 8 of 13.
Seema said:
1 decade ago
Hi friends please tell me how to solve this equation.
X/y-2 + 40/60 = X/y+3 -40/60.
X/y-2 + 40/60 = X/y+3 -40/60.
Mayur said:
10 years ago
Difference of speed and time = distance.
3 * 40 - 2 * 40 = x.
120 - 80 = x.
40 = x.
3 * 40 - 2 * 40 = x.
120 - 80 = x.
40 = x.
Sivaram said:
1 decade ago
There is simple method
3*40=120
2*40=80
Then subtract two we get 40 this simple
3*40=120
2*40=80
Then subtract two we get 40 this simple
Uroosa said:
9 years ago
@Sivaram.
How can you multiply km/hr with minutes without changing it to hours?
How can you multiply km/hr with minutes without changing it to hours?
Puneet negi said:
9 years ago
How can we get the answer in km when the time is given in minutes? @Shivraman.
Jiya said:
1 decade ago
Can somebody please solve this equation ->
X/y-2 + 40/60 = X/y+3 -40/60.
X/y-2 + 40/60 = X/y+3 -40/60.
Atchu said:
10 years ago
@Sivaram.
Is it the correct way and suitable to all this type of questions?
Is it the correct way and suitable to all this type of questions?
Prasanna said:
1 decade ago
Can any of you please explain how 2 solve that equations in detail please.
Gursewak singj said:
10 years ago
It is tough to find the solution. Can anybody solve it in a simple way?
Singh said:
9 years ago
Simplest formulae (S + 3)/(s - 2) = 3t2/2t1,
Solving we get s = 12km/h.
Solving we get s = 12km/h.
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