Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 15)
15.
A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
Answer: Option
Explanation:
Let distance = x km and usual rate = y kmph.
| Then, | x | - | x | = | 40 |  2y(y + 3) = 9x ....(i) |
| y | y + 3 | 60 |
| And, | x | - | x | = | 40 | y(y - 2) = 3x ....(ii) |
| y -2 | y | 60 |
On dividing (i) by (ii), we get: x = 40.
Discussion:
118 comments Page 7 of 12.
Singh said:
9 years ago
Simplest formulae (S + 3)/(s - 2) = 3t2/2t1,
Solving we get s = 12km/h.
Solving we get s = 12km/h.
Sridharan said:
9 years ago
How can I get the actual speed?
Manish said:
9 years ago
WE KNOW,
DISTANCE = SPEED * TIME.
Then,
(speed+3) * (time - 40/60) = (speed - 2) (time + 40/60) = distance, I am not getting answer,
Can anyone explain by this method?
DISTANCE = SPEED * TIME.
Then,
(speed+3) * (time - 40/60) = (speed - 2) (time + 40/60) = distance, I am not getting answer,
Can anyone explain by this method?
Harjeet said:
9 years ago
@Pauli.
45.
.5 = 90/x - 90/x + 15.
45.
.5 = 90/x - 90/x + 15.
Dhivakar said:
9 years ago
If 3km/hr faster than actual speed, it takes 40 minutes less time to complete.
If 2km/hr slower, it takes 40 minutes more.
So,
If we take condition 1, it would be 2km more than the actual distance at the actual time.(3km/hr, so 2km in 40 minutes)
If we take condition 2, it would be 4/3 km less than the actual distance at the actual time.(2km/hr, so 4/3 km in 40 minutes)
Now the difference between the two condition is 80 minutes and the distance is 2 + 4/3.
Distance = speed * time.
So, we equate, 10/3 = x/80 * 60(multiplying 60 is for hour conversion).
So, x = 40.
If 2km/hr slower, it takes 40 minutes more.
So,
If we take condition 1, it would be 2km more than the actual distance at the actual time.(3km/hr, so 2km in 40 minutes)
If we take condition 2, it would be 4/3 km less than the actual distance at the actual time.(2km/hr, so 4/3 km in 40 minutes)
Now the difference between the two condition is 80 minutes and the distance is 2 + 4/3.
Distance = speed * time.
So, we equate, 10/3 = x/80 * 60(multiplying 60 is for hour conversion).
So, x = 40.
Gursewak singj said:
9 years ago
It is tough to find the solution. Can anybody solve it in a simple way?
Sidzwozz said:
9 years ago
@Pauli.
According to my calculations, Jake has 4.5 Km/Hour. Let me know whether it's wrong or Right?
According to my calculations, Jake has 4.5 Km/Hour. Let me know whether it's wrong or Right?
PaulI said:
9 years ago
How about this question?
Had Jake traveled 15 kph faster, the 90 km trip would have taken him 30 mins earlier. What is his speed?
Had Jake traveled 15 kph faster, the 90 km trip would have taken him 30 mins earlier. What is his speed?
Mayur said:
9 years ago
Difference of speed and time = distance.
3 * 40 - 2 * 40 = x.
120 - 80 = x.
40 = x.
3 * 40 - 2 * 40 = x.
120 - 80 = x.
40 = x.
Nagurum said:
9 years ago
@Zaid.
After finding the time and I cannot find the distance value, how to solve? Please help me.
After finding the time and I cannot find the distance value, how to solve? Please help me.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers