Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 7)
7.
A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
Answer: Option
Explanation:
(1/2)x | + | (1/2)x | = 10 |
21 | 24 |
![]() |
x | + | x | = 20 |
21 | 24 |
15x = 168 x 20
![]() |
![]() |
168 x 20 | ![]() |
= 224 km. |
15 |
Discussion:
141 comments Page 9 of 15.
Velu said:
1 decade ago
There said half the journey. So why didn't we get half the time for calculation.
Like (5*24)+(5*21) = 225.
Like (5*24)+(5*21) = 225.
MALLIKARJUN said:
1 decade ago
Simple trick.
Find average speed because they are given half and half journey.
2xy/x+y......> 2(21)(24)/(21+24).
So average speed = 2(21)(24)/45.
Therefore D = S*T.
= [2(21)(24)/45]*10 = 224.
Find average speed because they are given half and half journey.
2xy/x+y......> 2(21)(24)/(21+24).
So average speed = 2(21)(24)/45.
Therefore D = S*T.
= [2(21)(24)/45]*10 = 224.
Damodhar said:
1 decade ago
Average speed = (2*21*24)/(21+24) = 102/5.
Distance = (102*10)/5 = 224.
Distance = (102*10)/5 = 224.
Sukumar Satyen said:
1 decade ago
Following is explanation:
Total Travel Time = 10 hours.
Let's assume Total Distance = d kms and 1st half (i.e d/2) was completed in x hours at speed of 21 kmph.
=> d/2 = 21x.
=> d/42 = x.....equation (1).
=> 2nd half (i.e d/2) was completed in (10-x) hours @ speed of 24 kmph.
=> d/2 = 24*(10-x).
=> d/48 = 10-x.
=> x = 10-(d/48)....equation (2).
From equation (1) and (2),
=> d/42 = 10-(d/48).
=> d/42 + d/48 = 10.
=> d = 2*5*2*3*7*8/(3*5).
=> d = 224 kms.
Total Travel Time = 10 hours.
Let's assume Total Distance = d kms and 1st half (i.e d/2) was completed in x hours at speed of 21 kmph.
=> d/2 = 21x.
=> d/42 = x.....equation (1).
=> 2nd half (i.e d/2) was completed in (10-x) hours @ speed of 24 kmph.
=> d/2 = 24*(10-x).
=> d/48 = 10-x.
=> x = 10-(d/48)....equation (2).
From equation (1) and (2),
=> d/42 = 10-(d/48).
=> d/42 + d/48 = 10.
=> d = 2*5*2*3*7*8/(3*5).
=> d = 224 kms.
Sandeep kumar said:
1 decade ago
First half of journey means half distance of journey. Not half ours of time. May it will help you.
Surya said:
1 decade ago
To apply formula 2uv/(u+v),
Where,
s = Distance;
u = First Half velocity which is 21 kmph.
v = Second Half Velocity which is 24 kmph.
=> (2*21*24)/(21+24).
=> (1008)/45.
=>22.4 kmph.
Therefore, average speed = 22.4 km/hr.
s = vt.
s = 22.4 km/hr x 10hrs.
s = 224 km.
Where,
s = Distance;
u = First Half velocity which is 21 kmph.
v = Second Half Velocity which is 24 kmph.
=> (2*21*24)/(21+24).
=> (1008)/45.
=>22.4 kmph.
Therefore, average speed = 22.4 km/hr.
s = vt.
s = 22.4 km/hr x 10hrs.
s = 224 km.
Sneha said:
10 years ago
I ll tell you people the easiest method.
Average speed = 2xy/(x+y) = 22.4.
Time is given 10 hrs.
So 10x22.4 = 224.
Average speed = 2xy/(x+y) = 22.4.
Time is given 10 hrs.
So 10x22.4 = 224.
Prateek said:
10 years ago
How does 15x arrived?
Salman said:
10 years ago
Here you need to know first that average speed is the uniform speed.
That is if the person travelled with the uniform speed then he would complete the journey in 10 hrs and cover the given distance as well. We don't know the distance and we are given two different speeds for half the journey.
Now as we can see the last formula in the important formula section for this chapter. We can get the average speed as: 2xy/(x+y).
So average speed = 2x21x24/(21+24).
Now not getting the exact average speed I reduce the above by basic division as.
Average speed = (2x7x8)/5.
But Distance = Speed*Time.
So, D = [(2x7x8)/5]*10 (Now 10/5 is 2 so the equation becomes).
2*7*8*2 = 224 km that's it!
That is if the person travelled with the uniform speed then he would complete the journey in 10 hrs and cover the given distance as well. We don't know the distance and we are given two different speeds for half the journey.
Now as we can see the last formula in the important formula section for this chapter. We can get the average speed as: 2xy/(x+y).
So average speed = 2x21x24/(21+24).
Now not getting the exact average speed I reduce the above by basic division as.
Average speed = (2x7x8)/5.
But Distance = Speed*Time.
So, D = [(2x7x8)/5]*10 (Now 10/5 is 2 so the equation becomes).
2*7*8*2 = 224 km that's it!
Sakthivel said:
10 years ago
First half of the journey is 21 km, 24 km.
Average speed during 21 km, 24 km = 2xy/x+y.
= 2 (21*24) /21+24.
= 1008/45 = 112/5.
He complete the hole journey in 10 hrs.
So, 112/5*10 = 224.
Thank you!
Average speed during 21 km, 24 km = 2xy/x+y.
= 2 (21*24) /21+24.
= 1008/45 = 112/5.
He complete the hole journey in 10 hrs.
So, 112/5*10 = 224.
Thank you!
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