Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 7)
7.
A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
Answer: Option
Explanation:
| (1/2)x | + | (1/2)x | = 10 |
| 21 | 24 |
 |
x | + | x | = 20 |
| 21 | 24 |
15x = 168 x 20
| x = |
 |
168 x 20 |  |
= 224 km. |
| 15 |
Discussion:
141 comments Page 14 of 15.
L J Jaswanth said:
2 years ago
WKT,
Average speed over two different speeds in the journey is;
Avg speed= (2XY/X+Y)km/h or M/S.
Where X is the speed during the first half (km/hr or m/s).
And Y is the speed during the second half (km/hr or m/s).
And WKT.
s= d/t and d=s*t.
Here Given
X=21 km/hr.
Y =24 km/hr.
And time over the whole jouneny is 10hrs,
Avg speed = (21*24)/(21+24),
= 22.4 km/hr.
And Total Distance =s*t.
22.4 * 10 = 224 km.
Average speed over two different speeds in the journey is;
Avg speed= (2XY/X+Y)km/h or M/S.
Where X is the speed during the first half (km/hr or m/s).
And Y is the speed during the second half (km/hr or m/s).
And WKT.
s= d/t and d=s*t.
Here Given
X=21 km/hr.
Y =24 km/hr.
And time over the whole jouneny is 10hrs,
Avg speed = (21*24)/(21+24),
= 22.4 km/hr.
And Total Distance =s*t.
22.4 * 10 = 224 km.
(22)
AANI said:
2 years ago
Total journey = 10 hours.
Journey in 2 parts 10/2 = 5
each journey is = 5 hours.
1st journey speed =21 km/hr ;
Total of 1st journey speed = 21 x 5 =105
Total of 2nd journey speed =24 x 5 =120.
Then,
Total 1st and 2nd both journey speed = 105 + 120 = 225 km.
THANKS.
Journey in 2 parts 10/2 = 5
each journey is = 5 hours.
1st journey speed =21 km/hr ;
Total of 1st journey speed = 21 x 5 =105
Total of 2nd journey speed =24 x 5 =120.
Then,
Total 1st and 2nd both journey speed = 105 + 120 = 225 km.
THANKS.
(386)
Ravinder Choudhary said:
2 years ago
X/21 + X/24 = 10,
15X/168 = 10,
X = 112,
2X = 224.
15X/168 = 10,
X = 112,
2X = 224.
(18)
Francis K Joseph said:
2 years ago
Let's take a formula = 2XY/X + Y.
Here, X=21 and Y= 24.
so, the formula is = 2 * 21 * 24/21 + 24,
=1008/45.
Here, your Answer = 22.4 * 10 = 224.
Here, X=21 and Y= 24.
so, the formula is = 2 * 21 * 24/21 + 24,
=1008/45.
Here, your Answer = 22.4 * 10 = 224.
(22)
Pradumn said:
1 year ago
By using the formula = 2xy/x + y.
= 2 * 21 * 24/21 + 24.
= 1008/45,
= 22.4,
= 22.4 * 10.
= 224km.
= 2 * 21 * 24/21 + 24.
= 1008/45,
= 22.4,
= 22.4 * 10.
= 224km.
(33)
Hardik H Bagaria said:
1 year ago
@All.
For the people who got an answer as 225km, we cannot assume that the time taken to complete half of the journey (distance) is 5hrs, assuming 5hrs for the first trip and 5 for the second is wrong.
Because its not relative to the time, but rather relative to the journey (distance).
For the people who got an answer as 225km, we cannot assume that the time taken to complete half of the journey (distance) is 5hrs, assuming 5hrs for the first trip and 5 for the second is wrong.
Because its not relative to the time, but rather relative to the journey (distance).
(48)
Gowthaman said:
1 year ago
Let's take a formula = 2XY/X + Y.
Here, X=21 and Y= 24.
So, the formula is = 2 * 21 * 24/21 + 24,
= 1008/45.
Here, your Answer = 22.4 * 10 = 224.
Here, X=21 and Y= 24.
So, the formula is = 2 * 21 * 24/21 + 24,
= 1008/45.
Here, your Answer = 22.4 * 10 = 224.
(32)
Himanshu said:
10 months ago
Let the Distance = 2x.
So, By Formula T = D/S.
The distance covered by each = x.
10 = x/21+x/24,
5040 = 45x,
X = 122.
So Distance =2x,
= 2x122,
=224 Km.
So, By Formula T = D/S.
The distance covered by each = x.
10 = x/21+x/24,
5040 = 45x,
X = 122.
So Distance =2x,
= 2x122,
=224 Km.
(21)
Ansh Raghav said:
9 months ago
@ALL.
According to the given question;
x/21 + x/24 =10
15x/168 = 10.
By cross multiplication;
168 × 10 = 15x.
1680 = 15x.
122 = x.
2x = 224.
According to the given question;
x/21 + x/24 =10
15x/168 = 10.
By cross multiplication;
168 × 10 = 15x.
1680 = 15x.
122 = x.
2x = 224.
(22)
Nithin said:
7 months ago
The right answer is 234 km.
(4)
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