Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 7)
7.
A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
220 km
224 km
230 km
234 km
Answer: Option
Explanation:

(1/2)x + (1/2)x = 10
21 24

x + x = 20
21 24

15x = 168 x 20

x = 168 x 20 = 224 km.
15

Discussion:
141 comments Page 10 of 15.

Muskan said:   5 years ago
AVG.speed=2v1*v2/V1+V2
= 2*21*24/21+24
=22.4km/h.
Distance = speed * time.
=22.4 *10
= 224km.

Pavan V D said:   1 decade ago
(1/2)x/21+(1/2)x/24 = 10.
x/21+x/24 = 20.

Take LCM,
45x/504 = 20.

x/11.2 = 20.
x = 224.0km.

Abhishek said:   1 decade ago
(x/21)+(x/24)=20;
taking LCM,we get-
(45x/504)=20;
and 45/504=15/168;
so 15x=168*20;
x=224;

Sajan said:   1 decade ago
Simple formula is 2t(s1*s2)/s1+s2.

So, 2*10(21*24)/21+24.

= 20*504/45.

= 20*11.2.

= 224.

Subham said:   9 years ago
d = (2 * T * x * y)/(x + y) formula can also be used where x and y are two different speed.

Abhik said:   1 decade ago
Avg speed = 2xy/x+y = 2.21.24/(21+24)= 112/5

distance= speed * tym = 112/5 * 10 = 224....

Ab rahuman said:   1 decade ago
Use average speed formula 2xy/x+y and multiply with time.

Since Distance = Time*Speed.

Mohit said:   1 decade ago
Can't we solve like this:

21*5=105 and 24*5=5 which equal to 225 instead of 224 why?

Chandan pal said:   1 decade ago
Avg speed: 2xy/x+y.

Avg speed: 2*21*24/21+24 = 112/5.

Distance = (112/5)*10 = 224.

Bhavin said:   3 years ago
x/21 + x/24 = 20.
24x + 21x = 20* 21 *24,
45x = 10,080,
x =10,080/45.
Ans x = 224.
(8)


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