# Aptitude - Surds and Indices - Discussion

Discussion Forum : Surds and Indices - General Questions (Q.No. 2)

2.

If | a |
x - 1 |
= | b |
x - 3 |
, then the value of x is: |
||||

b |
a |

Answer: Option

Explanation:

Given | a |
x - 1 |
= | b |
x - 3 |
|||

b |
a |

a |
x - 1 |
= | a |
-(x - 3) |
= | a |
(3 - x) |
|||||||

b | b | b |

*x* - 1 = 3 - *x*

2*x* = 4

*x* = 2.

Discussion:

26 comments Page 3 of 3.
Yashi Jain said:
1 decade ago

How could you add the powers when there is an = sign between the two.

Nisikanta said:
1 decade ago

(a/b)^x-1= (b/a)^x-3

* Remember, sinplification is always solved by 2 or more fraction or number or alphabet.

:If the alphabet fraction is not equal to one anthor,we have reranged it.

= (a/b)^x-1= (a/b)^-(x-3)= (a/b)^(3-x)

: Then we have to take power for simplification.

= x-1= 3-x

* When the number goes after or before '=' sign the sign changes

: Now we have to change the places.

= 2x=4

=x=2

* Remember, sinplification is always solved by 2 or more fraction or number or alphabet.

:If the alphabet fraction is not equal to one anthor,we have reranged it.

= (a/b)^x-1= (a/b)^-(x-3)= (a/b)^(3-x)

: Then we have to take power for simplification.

= x-1= 3-x

* When the number goes after or before '=' sign the sign changes

: Now we have to change the places.

= 2x=4

=x=2

Basavaraju said:
1 decade ago

I can not understand.

Nem prasad said:
1 decade ago

Can anybody tell me what is the concept through which this problem has been solved ?

Ravi kiran said:
1 decade ago

@pooja

(b/a) can be written as (a/b)^-1.

Based on this concept this problem is solved.

(b/a) can be written as (a/b)^-1.

Based on this concept this problem is solved.

Pooja said:
1 decade ago

I didn't understand for solve the method. Please explain.

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