Aptitude - Surds and Indices - Discussion
Discussion Forum : Surds and Indices - General Questions (Q.No. 2)
2.
| If |  |
a |  |
x - 1 | = | |
b | |
x - 3 | , then the value of x is: |
| b | a |
Answer: Option
Explanation:
| Given |
a | |
x - 1 | = | |
b | |
x - 3 |
| b | a |
 |
|
a | |
x - 1 | = | |
a | |
-(x - 3) | = | |
a | |
(3 - x) |
| b | b | b |
x - 1 = 3 - x
2x = 4
x = 2.
Discussion:
26 comments Page 2 of 3.
Yammu said:
9 years ago
If (b/a) reciprocal how will power gets negative?
AkshI gori said:
9 years ago
Not understanding it. Please help me to get it.
Husain SR said:
9 years ago
Here (a/b)^x-1 and (b/a)^x-3 now if we reciprocal b/a to a/b then there is negative sign on it.
(a/b)^-(x-3).
Let compare thier powers;
x - 1 = -(x - 3).
x - 1 = -x + 3
x + x = 1 + 3.
2x = 4
x = 2 is answer.
(a/b)^-(x-3).
Let compare thier powers;
x - 1 = -(x - 3).
x - 1 = -x + 3
x + x = 1 + 3.
2x = 4
x = 2 is answer.
(1)
Lawal Adetunji said:
8 years ago
I am not getting this. Please help me to understand better.
Heman said:
8 years ago
(a/b)^x-1=(b/a)x-3.
=>a^x/b^1=a^-3/b^-x,
=>a/b^x-1=a/b^3-x,
=>x-1=3-1,
=>x=2.
=>a^x/b^1=a^-3/b^-x,
=>a/b^x-1=a/b^3-x,
=>x-1=3-1,
=>x=2.
Priya said:
8 years ago
I am not understanding this method. Please explain me in detail.
Sachin d said:
8 years ago
Thanks @Heman.
(1)
Priyadharshini said:
8 years ago
I can understand very easily. Thank you @Heman.
Hemz said:
8 years ago
Thanks @Heman.
Shweta said:
7 years ago
@Husain.
When you compare the power then , x-1=-x-3.
Then how you change the sign of ,x-1=x+3?
When you compare the power then , x-1=-x-3.
Then how you change the sign of ,x-1=x+3?
(1)
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