Aptitude - Square Root and Cube Root - Discussion
Discussion Forum : Square Root and Cube Root - General Questions (Q.No. 7)
7.
| If x = | 3 + 1 | and y = | 3 - 1 | , then the value of (x2 + y2) is: |
| 3 - 1 | 3 + 1 |
Answer: Option
Explanation:
| x = | (3 + 1) | x | (3 + 1) | = | (3 + 1)2 | = | 3 + 1 + 23 | = 2 + 3. |
| (3 - 1) | (3 + 1) | (3 - 1) | 2 |
| y = | (3 - 1) | x | (3 - 1) | = | (3 - 1)2 | = | 3 + 1 - 23 | = 2 - 3. |
| (3 + 1) | (3 - 1) | (3 - 1) | 2 |
x2 + y2 = (2 + 3)2 + (2 - 3)2
= 2(4 + 3)
= 14
Discussion:
45 comments Page 5 of 5.
Mayur said:
1 decade ago
Hello M.V.Krishna
You are absolutely right
Thank you....
You are absolutely right
Thank you....
M.V.KRISHNA/PALVONCHA said:
1 decade ago
Hello gaurav and tank mayur.
This is the process of rationalization.
The denominator is multiplied and divided to selected value.
Hope you understand.
This is the process of rationalization.
The denominator is multiplied and divided to selected value.
Hope you understand.
Tank Mayur B. said:
1 decade ago
This is wrong solution .
because: ((a+b)/(a-b))*((a+b)/(a+b))=(a+b)2/(a2 + b2)
because: ((a+b)/(a-b))*((a+b)/(a+b))=(a+b)2/(a2 + b2)
Gaurav said:
1 decade ago
Asnwer to this seems to be '-10'.
Nithin said:
1 decade ago
(a+b)2 + (a-b)2 = 2(a2 + b2)
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