Aptitude - Square Root and Cube Root - Discussion
Discussion Forum : Square Root and Cube Root - General Questions (Q.No. 10)
10.
| If 5 = 2.236, then the value of | 5 | - | 10 | + 125 is equal to: |
| 2 | 5 |
Answer: Option
Explanation:
| 5 | - | 10 | + 125 | = | (5)2 - 20 + 25 x 55 |
| 2 | 5 | 25 |
| = | 5 - 20 + 50 |
| 25 |
| = | 35 | x | 5 |
| 25 | 5 |
| = | 355 |
| 10 |
| = | 7 x 2.236 |
| 2 |
| = 7 x 1.118 |
| = 7.826 |
Discussion:
11 comments Page 1 of 2.
Sri Satya Kanamarlapudi said:
5 years ago
It can be also rewritten as (√(5) √(5)/2) - (2*√(5)√(5)/√(5))+(5*√(5)).
√(5)/2 - 2√(5) +5√(5).
7√(5)/2 = 7.826.
√(5)/2 - 2√(5) +5√(5).
7√(5)/2 = 7.826.
Kongkon said:
6 years ago
I don't understand. Can anyone explain me please?
Vipinkumar said:
7 years ago
You are right @Mannoj Kumar.
@Anuj.
If we take common term sqrt(5) from each term so that we get;
In first term: sqrt 5[ 1/2 ].
In second term: sqrt5 [10/((sqrt5)/sqrt5)] = sqrt5[10/(sqrt5 * sqrt5)]
= sqrt5[10/5].
In third term: sqrt5[(5 * sqrt5)/sqrt5] = sqrt5[5].
In these three terms, sqrt5 is common and take it outside the bracket and apply it in the expression(question)so we get.
= sq5[ 1/2 - 10/5 + 5].
= 2.236[ 0.5 -2 + 5].
= 2.236 * 3.5.
= 7.82600.
@Anuj.
If we take common term sqrt(5) from each term so that we get;
In first term: sqrt 5[ 1/2 ].
In second term: sqrt5 [10/((sqrt5)/sqrt5)] = sqrt5[10/(sqrt5 * sqrt5)]
= sqrt5[10/5].
In third term: sqrt5[(5 * sqrt5)/sqrt5] = sqrt5[5].
In these three terms, sqrt5 is common and take it outside the bracket and apply it in the expression(question)so we get.
= sq5[ 1/2 - 10/5 + 5].
= 2.236[ 0.5 -2 + 5].
= 2.236 * 3.5.
= 7.82600.
Kanchan said:
7 years ago
How to solve root?
Shradha said:
8 years ago
No need to multiply root five to both side.
Tejas said:
8 years ago
How it come 2 root 5?
Avinash said:
9 years ago
rt5/2 - 10/rt5 + rt125.
Just put value of rt5 and calculate.
2.236/2 - 10/2.236 + 5*2.236 = 7.826.
It's simple.
Just put value of rt5 and calculate.
2.236/2 - 10/2.236 + 5*2.236 = 7.826.
It's simple.
Radhika said:
1 decade ago
Why we multiply with squreroot 5 on both sides.
M.V.KRISHNA/PALVONCHA said:
1 decade ago
Hello Anuj.
root=r.
Given (r5/2)-(10/r5)+r125.
10/r5 = 2*5/r5 = 2r5.
r125 = 5r5
(r5/2)-2r5+5r5
(r5/2)+3r5
(r5+6r5)/2
7r5/2
Subst. given r5 value we get 7.826.
Hope you understood.
root=r.
Given (r5/2)-(10/r5)+r125.
10/r5 = 2*5/r5 = 2r5.
r125 = 5r5
(r5/2)-2r5+5r5
(r5/2)+3r5
(r5+6r5)/2
7r5/2
Subst. given r5 value we get 7.826.
Hope you understood.
Anuj said:
1 decade ago
How you calculate 10/5 ?
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