Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 2)
2.
There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
Answer: Option
Explanation:
Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 
x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Discussion:
75 comments Page 7 of 8.
Akshay said:
8 years ago
Nice explanation, Thanks @Manojkumar.
Sandy said:
1 decade ago
Can you explain by assuming a = 100?
Cgyel said:
9 years ago
If A is double then, Why 2 (y - 20)?
Geetha said:
6 years ago
Please Explain the 2nd step.
Rcahana said:
1 decade ago
Please help me solve this.
Nagesh v said:
7 years ago
Thank for you answer @Ash.
Suresh said:
6 years ago
In step 1 how you got 100?
(1)
Temmy said:
8 years ago
How did they get the y=80?
Srinu said:
8 years ago
Nice explanation. Thanks.
Saurya said:
6 years ago
Thank all for explaining.
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