Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 2)
2.
There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
Answer: Option
Explanation:
Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 
x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Discussion:
75 comments Page 4 of 8.
Garry said:
7 years ago
Accroding to last condtion, It should be 2(x+20).
Nagesh v said:
7 years ago
Thank for you answer @Ash.
Kaleem said:
7 years ago
Thank you all.
Saurya said:
6 years ago
Thank all for explaining.
Suman said:
9 years ago
Well explained @Tamil.
Geetha said:
6 years ago
Please Explain the 2nd step.
Sagar said:
6 years ago
Thanks @Naga invy.
Prakash said:
6 years ago
Could you please explain this? I am not getting it.
Raji said:
1 decade ago
Its simple given second condition that by sending 20 people A is twice of B so A+20=2(B-20) and solving both conditions we get 100
Nandhakumar said:
1 decade ago
Then the number of students in A is double the number of students in B" so the step was look like 2(x+20) = (y-20). Then how it come(x+20) = 2(y-20).
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