Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 15)
15.
David gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Albert gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross ?
19
28
30
37
Answer: Option
Explanation:

Suppose their paths cross after x minutes.

Then, 11 + 57x = 51 - 63x       120x = 40

x = 1
3

Number of floors covered by David in (1/3) min. = 1 x 57 = 19.
3

So, their paths cross at (11 +19) i.e., 30th floor.

Discussion:
28 comments Page 3 of 3.

Mukesh said:   10 years ago
@Mani.

You are cool, this is the best way and the easiest way.

Mani said:   1 decade ago
s = d/t.
In this problem time travel is same for both=> d1/s1 = d2/s2.

Lets assume they cross the paths at yth floor.
(y-11)/57=(51-y)/63.

Solve this,
y=30.

Amit said:   1 decade ago
@Geeni.

Just implemented the concept of relative velocity.

1/3 is time at which david and albert meet. So he multiply that time to the velocity of david and calculate the distance travelled by david and finally he added that distance to david's initial position.

Subhadip said:   1 decade ago
Just visualize the problem solve & understand last step.

Deepti said:   1 decade ago
Can someone explain how you got 11+(1/3)*57b = b51-(1/3)*63?

Hardik said:   1 decade ago
@Geeni

Please explain last step
11+(1/3)*57=51-(1/3)*63

Rehana said:   1 decade ago
Its 40f/120f/m=1/3min

Nje said:   1 decade ago
Geeni you're a genius.


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