Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 4)
4.
If a - b = 3 and a2 + b2 = 29, find the value of ab.
Answer: Option
Explanation:
2ab = (a2 + b2) - (a - b)2
= 29 - 9 = 20
ab = 10.
Discussion:
107 comments Page 3 of 11.
Bhavana said:
1 decade ago
I didn't get the fifth line. Can you explain it.
Krishna said:
1 decade ago
a^2+b^2=(a-b)(a-b)+2ab. Now putting the value of (a-b)we get that 9+2ab=29, 2ab=20, ab=10.
Krishna said:
1 decade ago
a2+b2=(a-b)(a-b)+2ab hota hi 3*3+2ab=29,2ab=20,ab=10
Suganya said:
1 decade ago
Sathish said correct solution and take a time shortly to solve the problem.
Ram said:
1 decade ago
(a+b)^2-(a-b)^2 = 4ab.
Arshiya said:
1 decade ago
If (a-b) = 7 ab = 9, then find the value of (a2+b2)?
Prasad said:
1 decade ago
(a-b)^2 = a^2+b^2-2ab.
Then 2ab = (a^2+b^2)-(a-b)^2.
2ab = 29-(3)^2.
2ab = 20.
ab = 10.
Then 2ab = (a^2+b^2)-(a-b)^2.
2ab = 29-(3)^2.
2ab = 20.
ab = 10.
Manjunatha dv said:
1 decade ago
a-b = 3.
5-2 = 3.
a^2+b^2 = 29.
5^2+2^2 = 29.
Answer = 5*2 = 29.
5-2 = 3.
a^2+b^2 = 29.
5^2+2^2 = 29.
Answer = 5*2 = 29.
Harisha said:
10 years ago
Solve the problem if a+1/a-2=4. Find the value of (a-2)^2+(1/a-2)^2?
Jisha said:
10 years ago
@Harisha can you explain your question?
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