Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 4)
4.
If a - b = 3 and a2 + b2 = 29, find the value of ab.
Answer: Option
Explanation:
2ab = (a2 + b2) - (a - b)2
= 29 - 9 = 20
ab = 10.
Discussion:
107 comments Page 2 of 11.
Sakshi said:
7 years ago
Thanks @Satish.
Jan said:
7 years ago
(a-b)^2 = a^2+b^2-2ab.
(3)^2 = 29-2ab,
9 = 29-2ab,
9-29 = -2ab,
-20 = -2ab,
10 = ab.
(3)^2 = 29-2ab,
9 = 29-2ab,
9-29 = -2ab,
-20 = -2ab,
10 = ab.
(1)
Jan said:
7 years ago
(a-b)^2 = a^2+b^2-2ab.
(3)^2 = 29-2ab,
9 = 29-2ab,
9-29 = -2ab,
-20 = -2ab,
10 = ab.
(3)^2 = 29-2ab,
9 = 29-2ab,
9-29 = -2ab,
-20 = -2ab,
10 = ab.
(1)
Saritha said:
7 years ago
it is given that (a-b)=3 and a^2+b^2=29.
So,
(a-b)^2=a^2+b^2-2ab.
{substitute a-b=3 and a^2+b^2=29}
=>3^2=29-2ab,
=>2ab=20,
=> ab=10.
So,
(a-b)^2=a^2+b^2-2ab.
{substitute a-b=3 and a^2+b^2=29}
=>3^2=29-2ab,
=>2ab=20,
=> ab=10.
(1)
Prince said:
7 years ago
We can write a^2+b^2=(a-b)^2+2ab.
When we solve (a-b)^2+2ab we will get a^2+b^2.
Now put the value of (a-b) and a^2+b^2 in the equation a^2+b^2=(a-b)^2+2ab.
Ans is - 10.
When we solve (a-b)^2+2ab we will get a^2+b^2.
Now put the value of (a-b) and a^2+b^2 in the equation a^2+b^2=(a-b)^2+2ab.
Ans is - 10.
Sivakumar said:
7 years ago
Please explain the formula clearly.
Ashraf said:
7 years ago
I can't understand. Please explain me.
Laxmi said:
7 years ago
What will be the answer, if a+b=5, a^2 + b^2 =30, Find b.
Anyone olve it.
Anyone olve it.
(1)
Shilpi said:
8 years ago
I can't understand it, please explain me.
Mohamed said:
8 years ago
Can anyone explain this to me I found it confused it.
If (a+b) / (a-b) +3/7, what is the value a/b?
If (a+b) / (a-b) +3/7, what is the value a/b?
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