Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 4)
4.
If a - b = 3 and a2 + b2 = 29, find the value of ab.
10
12
15
18
Answer: Option
Explanation:

2ab = (a2 + b2) - (a - b)2

   = 29 - 9 = 20

   ab = 10.

Discussion:
107 comments Page 10 of 11.

Anita said:   1 decade ago
a = 2, b = 5.

a-b = 3.

2*2 + 5*5.

4+25 = 29.

Then ab = 10.

Deep goel said:   1 decade ago
a+b=3 a-b=1 then ab=?

((a+b)^2-(a-b)^2)/4=ab :^2=squaring.

(3^2-1^2)/4= ab.
(9-1)/4=ab.
8/4=2=ab.

Satheesh M said:   1 decade ago
a^2 + b^2 = 29
a^2 + b^2 = 5x5 + 2x2
a^2 + b^2 = 25+4
so that a = 5 and b = 2
then ab = 5x2 => 10

Lokmani said:   1 decade ago
a-b=3
a^2+b^2=29
(a-b)^2=a^2+b^2-2ab
(3)^2=29-2ab
9=29-2ab
2ab=29-9
2ab=20
ab=20/2
ab=10

Gurpreet singh said:   1 decade ago
a-b=3 and a^2+b^2=29.
Firstly a-b=3.
Squaring both sides,we get (a-b)^2=3^2.
a^2+b^2-2.ab=9.

a^2+b^2=29 ............(1).
a^2+b^2-2.ab=9.........(2).
Subtract (2) from (1)..

a^2+b^2-[a^2+b^2-2.ab] = 29-9.
a^2 + b^2 - a^2 - b^2 + 2.ab = 29-9.
2ab=20.
ab =20/2 = 10.

Jay said:   1 decade ago
I dont get the fifth line. kindly explain better.

Kavi said:   1 decade ago
a-b=3 and a2+b2=29
b=a-3 sub in above equ,
a2+(a-3)2=29
a2+a2-6a+9=29
a2-3a-10=0
a=5 or -2
let we taken a=5
5^2+b2=29
25+b2=29
b=2
ab=(5)(2)
ab=10

Sunita said:   1 decade ago
Where did 9 come from?

How did we arrive at 29-9?

Akash said:   1 decade ago
In a2+b2=29.
substract both side by 2ab.

Pritam das said:   1 decade ago
(a-b)^2+2ab=29
or,(3)^2+2ab=29
or,9+2ab=29
or,2ab=20
or,ab=10


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