Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 14)
14.
| (469 + 174)2 - (469 - 174)2 | = ? |
| (469 x 174) |
Answer: Option
Explanation:
| Given exp. = | (a + b)2 - (a - b)2 |
| ab |
| = | 4ab |
| ab |
= 4 (where a = 469, b = 174.)
Discussion:
15 comments Page 2 of 2.
Yugesh said:
1 decade ago
I can't able to find the answer.
Amrit said:
1 decade ago
Its very simple.
Its formula,
[(a+b)^2-(a-b)^2]/ab.
[(a^2+b^2+2ab)-(a^2+b^2-2ab)]/ab.
[a^2+b^2+2ab-a^2-b^2+2ab]/ab.
From here a^2-a^2 = 0, b^2-b^2 = 0, and 2ab+2ab = 4ab.
4ab/ab.
Now divide ab/ab i.e 1.
so 4*1 = 4.
Its formula,
[(a+b)^2-(a-b)^2]/ab.
[(a^2+b^2+2ab)-(a^2+b^2-2ab)]/ab.
[a^2+b^2+2ab-a^2-b^2+2ab]/ab.
From here a^2-a^2 = 0, b^2-b^2 = 0, and 2ab+2ab = 4ab.
4ab/ab.
Now divide ab/ab i.e 1.
so 4*1 = 4.
(4)
Afroz said:
1 decade ago
I did not come to know how 4ab has come as a answer so kindly send me the suggestion where I get answer.
Kavi said:
1 decade ago
How 4ab/ab come?
Naddy said:
1 decade ago
=[(a+b)^2-(a-b)^2]/ab
=[(a2+b2+2ab)-(a2-b2-2ab)]/ab
=4ab/ab,
where as a^2 and b^2 will get cancelled as both are in oppoaite signs
=4
=[(a2+b2+2ab)-(a2-b2-2ab)]/ab
=4ab/ab,
where as a^2 and b^2 will get cancelled as both are in oppoaite signs
=4
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