Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - Data Sufficiency 1 (Q.No. 1)
Directions to Solve
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
- Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
- Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
- Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
- Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
- Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
1.
The simple interest on a sum of money is Rs. 50. What is the sum? | |
I. | The interest rate is 10% p.a. |
II. | The sum earned simple interest in 10 years. |
Answer: Option
Explanation:
Given : S.I. = Rs. 50.
I gives, R = 10% p.a.
II gives, T = 10 years.
![]() |
![]() |
100 x S.I. | ![]() |
= Rs. | ![]() |
100 x 50 | ![]() |
= Rs. 50. |
T x R | 10 x 10 |
Thus, I and II together give the answer.
Correct answer is (E).
Discussion:
8 comments Page 1 of 1.
MAHBUBUR RAHMAN said:
4 years ago
Very good. I think it help us so much. Thanks all for explaing.
Harshitha said:
6 years ago
Thanks for explaining it @Blacky.
Gupta said:
7 years ago
Yes, right @Apuroop.
The Principal will be 500rs.
The Principal will be 500rs.
Apuroop said:
7 years ago
@Blacky.
The principal will be 500.
The principal will be 500.
(1)
Sanu said:
8 years ago
Good explanation @Blacky.
Pratik said:
8 years ago
Very good explanation, Thanks @Blacky.
Subha Das said:
1 decade ago
Very good. I think it help us so much.
Blacky said:
1 decade ago
I think option A will be enough to find the sum
SI=(P*T*R/100)
50=(P*T*R/100)
P=x; t=1; r=10 (10 % 'per' annum i.e. r=10 for 1 year)
50=(x*1*10/100)
x=50 ie Principal=50
SI=(P*T*R/100)
50=(P*T*R/100)
P=x; t=1; r=10 (10 % 'per' annum i.e. r=10 for 1 year)
50=(x*1*10/100)
x=50 ie Principal=50
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