Aptitude - Simple Interest - Discussion

Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Rs. 6400
Rs. 6500
Rs. 7200
Rs. 7500
None of these
Answer: Option
Explanation:

Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).

Then, x x 14 x 2 + (13900 - x) x 11 x 2 = 3508
100 100

28x - 22x = 350800 - (13900 x 22)

6x = 45000

x = 7500.

So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.

Video Explanation: https://youtu.be/Xi4kU9y6ppk

Discussion:
115 comments Page 9 of 12.

Loja said:   9 years ago
Can anyone explain in a simple way?

Jayesh said:   9 years ago
Can't we solve it using alligation and mixture?

Because I tried and could not get the answer.

Azly said:   9 years ago
We can solve this using simultaneous equations. Here we go!

Total interest for 2 years - 3508.
Then for a year - 3508/2 = 1754.
Assume investment in A scheme as x and B as Y.

14/100 * x + 11/100 * y = 1754 --------> 1st eqn
x + y = 13900 -------> 2nd eqn.

Solve this. You will get the answer.

Sumit said:   9 years ago
Please explain me. I can't understand this.

Naveen be cool said:   9 years ago
A = 14 * 2 yrs.
B = 11 * 2 yrs.

Now you'll get 28, & 22.
=> 28 + 22 = 50 * 3508 * 2 = 350800.
Now you need to find the amount of B = 22 * 13900 = 305800.
So. 350800 - 305800 = 45000 .
28 - 22 difference is = 6.
Now 45000/6 = 7500.
=> 13900 - 7500 = 6400.

Then the value of A is 7500 and B is 6400.

Venu sabbani said:   9 years ago
13900 is then two parts 14 * 2 and 11 * 2.
Then 28 and 22(scheme A and scheme B difference is 6%).

28% of 13900 = 3892.
3892 -> given amount, then3892 - 3508 = 384.
Two schemes difference is 6%(28 - 22).
6% = 384.
Sum 100% =?

Then cross multiplication 384 * 100/6 = 6400 is the answer.

Soumya said:   9 years ago
Can anyone explain it in Alligation method?

Bushra said:   9 years ago
What is the answer for the question?

A farmer has a rectangular garden plot surrounded by 200ft of the fence. Find the length and width of the garden if its area is 2400ft2.

PRANAV said:   9 years ago
@Bushra.

Area of rectangle = l * w
Perimeter of rectangle = 2 * (l + w)
--------------------------------------------

2 * (l + w) = 200
l + w = 100 ---> equa(1)

l * w = 2400
so, w = 2400/l ---> equa(2)
Putting equa(2) in equa(1).

We get,
l + (2400/l) = 100
l^2 + 2400 = 100 * l
l^2 - 100 * l -2400 = 0
l^2 - 60 * l - 40 * l -2400 = 0
l (l - 60) - 40 (l - 60) = 0
(l - 60) (l - 40) = 0

Hence, if l = 60 w = 40 (from equa(1))
Else, l = 40 then w = 60.

Harsha said:   9 years ago
Can anyone explain easily?


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