Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
| Then, |  |
x x 14 x 2 |  |
+ | |
(13900 - x) x 11 x 2 | |
= 3508 |
| 100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Video Explanation: https://youtu.be/Xi4kU9y6ppk
Discussion:
115 comments Page 6 of 12.
Jayesh said:
9 years ago
Anyone know the Shortcut method?
Narender said:
9 years ago
How to use it with alligation?
Nethi pradeep said:
9 years ago
Please explain me in simple method.
Saurabh chavan said:
9 years ago
Please, anybody explain it in a simple way.
Ans seekers said:
9 years ago
Sir, please explain in a simple way.
Chiran said:
9 years ago
Tell me how it became (13900 - x)?
Jayesh said:
9 years ago
Can't we solve it using alligation and mixture?
Because I tried and could not get the answer.
Because I tried and could not get the answer.
Loja said:
9 years ago
Can anyone explain in a simple way?
Maheswaran said:
9 years ago
Thanks for the solution and explanations.
Azly said:
9 years ago
We can solve this using simultaneous equations. Here we go!
Total interest for 2 years - 3508.
Then for a year - 3508/2 = 1754.
Assume investment in A scheme as x and B as Y.
14/100 * x + 11/100 * y = 1754 --------> 1st eqn
x + y = 13900 -------> 2nd eqn.
Solve this. You will get the answer.
Total interest for 2 years - 3508.
Then for a year - 3508/2 = 1754.
Assume investment in A scheme as x and B as Y.
14/100 * x + 11/100 * y = 1754 --------> 1st eqn
x + y = 13900 -------> 2nd eqn.
Solve this. You will get the answer.
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