Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
| Then, |  |
x x 14 x 2 |  |
+ | |
(13900 - x) x 11 x 2 | |
= 3508 |
| 100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Video Explanation: https://youtu.be/Xi4kU9y6ppk
Discussion:
115 comments Page 5 of 12.
Zakir said:
1 decade ago
Good thinking.
Ismail khan said:
1 decade ago
pin/100 + (13900-p)in/100=3508 where p is principle
i is interest rate and n is no.of years
p(28/100)+(13900-p)22/100=3508
28p+13900*22-22p=3508*100
28p-22p+305800=350800
6p=45ooo
p=7500
13900-7500=6400
i is interest rate and n is no.of years
p(28/100)+(13900-p)22/100=3508
28p+13900*22-22p=3508*100
28p-22p+305800=350800
6p=45ooo
p=7500
13900-7500=6400
Renu said:
1 decade ago
Formula is simple interest(S.I)=P*T*R/100;
P=Principal amount or sum
T=Time
R=Interest rate
By using this formula we can solve this.
P=Principal amount or sum
T=Time
R=Interest rate
By using this formula we can solve this.
Swati Alone said:
1 decade ago
Can anyone tell me how to do this answer easily and fast without using pen ?
Pranali said:
1 decade ago
Can someone please explain me the 2nd step 28X-22X = 350800 - (13900x22) how it came?
Rajesh said:
1 decade ago
Assume the amount invested in scheme B be 6400.
Then the amount invested in scheme A is 13900-6400 = 7500.
14% in 7500 = 1050.
For two years (1050*2) = 2100.
11% in 6400 = 704.
For two years (704*2) = 1408.
Adding these two gives (2100 + 1408) = 3508.
Therefore we assumed correctly and the answer is 6400.
Then the amount invested in scheme A is 13900-6400 = 7500.
14% in 7500 = 1050.
For two years (1050*2) = 2100.
11% in 6400 = 704.
For two years (704*2) = 1408.
Adding these two gives (2100 + 1408) = 3508.
Therefore we assumed correctly and the answer is 6400.
Chaitanya said:
1 decade ago
Is we use the formula ptr/100?
Bikash kumar said:
1 decade ago
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
Then, (X*14*2/100)+{(13900-X)*11*2/100} = 3508.
28x/100 + (13900*22)-(x*22)/100 = 3508.
28x/100 + 305800-22x/100 = 3508.
28x+305800-22x/100 = 3508.
Now,
28x+305800-22x=3508*100.
28x-22x=350800-305800.
6x=45000.
x=45000/6.
x=7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Then, (X*14*2/100)+{(13900-X)*11*2/100} = 3508.
28x/100 + (13900*22)-(x*22)/100 = 3508.
28x/100 + 305800-22x/100 = 3508.
28x+305800-22x/100 = 3508.
Now,
28x+305800-22x=3508*100.
28x-22x=350800-305800.
6x=45000.
x=45000/6.
x=7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Sameth said:
1 decade ago
What is Rs. Stand for?
MANI SMART said:
1 decade ago
The formula is (pnr/100).
p=inicial amount,
n=no of years,
r=rate of interest
p=inicial amount,
n=no of years,
r=rate of interest
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers