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Aptitude - Simple Interest - Discussion

Discussion Forum : Simple Interest - General Questions (Q.No. 2)
Simple Interest
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Rs. 6400
Rs. 6500
Rs. 7200
Rs. 7500
None of these
Answer: Option
Explanation:

Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).

Then, x x 14 x 2 + (13900 - x) x 11 x 2 = 3508
100 100

28x - 22x = 350800 - (13900 x 22)

6x = 45000

x = 7500.

So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.

Video Explanation: https://youtu.be/Xi4kU9y6ppk

Discussion:
115 comments Page 3 of 12.
Vikas said:   7 years ago
step 1= p*r*t/100.
step 2=A=X & B=Y,
step 3= (X*14/100*2/2)+(Y*11/100*2/2)=3508/2.
step 4=X+y=3508,
After calculation we get x and y value.
(1)
Monica Williams said:   7 years ago
3508 *100 (÷ will become*) so that's how we got 350800 in the 2nd step?
(1)
B Krishna said:   7 years ago
How did you Assume that 7500 here, in what basis did you get that, can we get a Clear Explanation on this?
(1)
Priya said:   6 years ago
How this is calculated? I didn't get please explain it.
(1)
Ajay said:   5 years ago
By using alligation method, we get;

13900/30*14 = 6500.
(1)
Dorji bhai said:   5 years ago
How denominator is getting cancelled while adding? Please explain about it.
(1)
Siva said:   5 years ago
I can't understand. If we use the formula ptr/100, how to identify 'r' in that? Please explain me.
(1)
Venu said:   2 decades ago
Can any one solve this in simple way?
Rajesh said:   2 decades ago
Use the method of alligation.
Suchita said:   2 decades ago
@Rajesh.

Can you please tell me that method.
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