Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
| Then, |  |
x x 14 x 2 |  |
+ | |
(13900 - x) x 11 x 2 | |
= 3508 |
| 100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Video Explanation: https://youtu.be/Xi4kU9y6ppk
Discussion:
115 comments Page 11 of 12.
Chiran said:
9 years ago
Tell me how it became (13900 - x)?
Sithara prasanth said:
9 years ago
How it can do through allegation.
Jayesh said:
9 years ago
Anyone know the Shortcut method?
Chandrasekar.S said:
9 years ago
Anyone can solve it in easy way?
Sree said:
7 years ago
Good explanation. Thank you all.
(1)
Chaitanya said:
1 decade ago
Is we use the formula ptr/100?
Narender said:
9 years ago
How to use it with alligation?
Rajesh said:
1 decade ago
Use the method of alligation.
Deepak said:
5 years ago
Thanks for explaining @Srini.
(4)
R.srinivasulu said:
1 decade ago
Shortcut method tell me sir.
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