Aptitude - Simple Interest - Discussion

Discussion Forum : Simple Interest - General Questions (Q.No. 9)
9.
A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?
3.6%
4.5%
5%
6%
None of these
Answer: Option
Explanation:

Let the original rate be R%. Then, new rate = (2R)%.

Note:
Here, original rate is for 1 year(s); the new rate is for only 4 months i.e. year(s).

725 x R x 1 + 362.50 x 2R x 1 = 33.50
100 100 x 3

(2175 + 725) R = 33.50 x 100 x 3

(2175 + 725) R = 10050

(2900)R = 10050

R = 10050 = 3.46
2900

Original rate = 3.46%

Discussion:
97 comments Page 10 of 10.

Muneer said:   10 years ago
How it comes 2175?

Kirti said:   10 years ago
Why it has been taken first for 1 year and after 8 years because in the question it has already mention that after 8 years he lended 362.50 and at the beginning he lended 725?

Venu said:   1 decade ago
Hey guys its correct.

Here 725 is given to the person for 1 year. Now you calculate the SI for that, later after 8 months, he again burrows again but the catch is rate is doubled.

Now you know :).

Agnes said:   1 decade ago
Please why did you multiply 33.50*100*3?

Sonu said:   1 decade ago
Hello sir,

Please let me know the right answer please.

Asif said:   1 decade ago
It should be:

725*r*8/(12*100) + 362.5*2r*4/(12*100) = 33.50.

R will be = 4.62%

Abhi said:   1 decade ago
Ya you should calculate for 8 months and 4 months.


Post your comments here:

Your comments will be displayed after verification.