Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 1)
1.
A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
Answer: Option
Explanation:
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
Discussion:
171 comments Page 4 of 18.
Yash said:
6 years ago
A sum of money at simple interest amounts to Rs. 815 in 3 years := P + SI(3 years) = 815
and to Rs. 854 in 4 years := P + SI(4 years) = 854.
p+(p*r*3)/100=815 ------> 1
p+(p*r*4)/100=854 -------> 2
on solving 1 and 2 you get := pr=3900.
put value of pr in eq-1 ,you get := p=698 (answer).
and to Rs. 854 in 4 years := P + SI(4 years) = 854.
p+(p*r*3)/100=815 ------> 1
p+(p*r*4)/100=854 -------> 2
on solving 1 and 2 you get := pr=3900.
put value of pr in eq-1 ,you get := p=698 (answer).
(2)
KRISHNA CHAURASIYA said:
5 years ago
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
And if you want to calculate from 854
then,
SI for 4 year =Rs(39*4)=156,
Principal =Rs (854 - 156)= 698.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
And if you want to calculate from 854
then,
SI for 4 year =Rs(39*4)=156,
Principal =Rs (854 - 156)= 698.
(2)
Arijit said:
5 years ago
P = (A2 * T1 - A1 * T2)/(T1 - T2).
(2)
Ranjit Das said:
5 years ago
@Kannan.
As we say here that we have found out the interest for 3 years i.e, 117. That's why we subtracted 117 from 815.
If, we calculate the interest for 4 years..the amount will be, (39*4)= 156, then we should subtract 156 from 854, the will be same as above.
As we say here that we have found out the interest for 3 years i.e, 117. That's why we subtracted 117 from 815.
If, we calculate the interest for 4 years..the amount will be, (39*4)= 156, then we should subtract 156 from 854, the will be same as above.
(2)
Adiba said:
4 years ago
Good explanation, Thanks all.
(2)
Sudarshan said:
4 years ago
Thanks @Appu.
(2)
Srada said:
4 months ago
Thanks all for explaining the answer clearly.
(2)
Name said:
1 decade ago
3y--815,
4y--854,
----------
1y--39,
So, 3y ---39 x 3 = 117
Principal is = (815-117) = 698
4y--854,
----------
1y--39,
So, 3y ---39 x 3 = 117
Principal is = (815-117) = 698
(1)
Vijay said:
1 decade ago
What is formula of simpe interest ?
(1)
Vikram said:
1 decade ago
According to the question,
SI + P = 815 in three years and
SI + P = 854 in four years
so 815 - P = SI and
854 - P = SI
Therefore,
815 - P = (P * 3 * R)/100 and ---- eq 1
854 - P = (P * 4 * R)/100 ---- eq 2
Now,
eq 1 / eq 2 gives
(815 - P)/(854 - P) = 3/4
Solving this eq, we get
P = 698
SI + P = 815 in three years and
SI + P = 854 in four years
so 815 - P = SI and
854 - P = SI
Therefore,
815 - P = (P * 3 * R)/100 and ---- eq 1
854 - P = (P * 4 * R)/100 ---- eq 2
Now,
eq 1 / eq 2 gives
(815 - P)/(854 - P) = 3/4
Solving this eq, we get
P = 698
(1)
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