Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 1)
1.
A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
Answer: Option
Explanation:
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
Discussion:
171 comments Page 2 of 18.
Vijay said:
1 decade ago
What is formula of simpe interest ?
(1)
Rajini kumar said:
1 decade ago
S.Ib = PNR/100
Narasimha reddy said:
1 decade ago
S.I=PTR/100
Gayathri said:
1 decade ago
Hi Friends!
Principle = the amt u borrowed
Interest = the small additional amt u pay for the amt u
borrowed
First let me explain u d question
In the question,
A sum of money at simple interest amounts to Rs. 815 in 3 years means the Principle amt together wit the interest paid for 3 yrs is Rs. 815 and similarly Principle amt together wit the interest paid for 4 yrs is Rs. 854
Therefore, if we subtract (854-815) we get the simple interest for 1 year as Rs. 39
Then, we calculate simple interest for 3 yrs as (39*3)= 117
Next step, we subtract (815 - 117) to get Principle amt for a yr as Rs. 698
Brief explanation for last step:
815 = Principle amt + int for 3 yrs ......equation 1
117 = int for 3 yrs ......equation 2
now subtract both equations, we get the principle amt
I hope tat this explanation will be helpful to u
Principle = the amt u borrowed
Interest = the small additional amt u pay for the amt u
borrowed
First let me explain u d question
In the question,
A sum of money at simple interest amounts to Rs. 815 in 3 years means the Principle amt together wit the interest paid for 3 yrs is Rs. 815 and similarly Principle amt together wit the interest paid for 4 yrs is Rs. 854
Therefore, if we subtract (854-815) we get the simple interest for 1 year as Rs. 39
Then, we calculate simple interest for 3 yrs as (39*3)= 117
Next step, we subtract (815 - 117) to get Principle amt for a yr as Rs. 698
Brief explanation for last step:
815 = Principle amt + int for 3 yrs ......equation 1
117 = int for 3 yrs ......equation 2
now subtract both equations, we get the principle amt
I hope tat this explanation will be helpful to u
(28)
Reshmi said:
1 decade ago
Thank you gayathri. You explained well.
Prathap said:
1 decade ago
Simple and clear explanation by gayatri.
Raghu karthic said:
1 decade ago
Superb explanation gayathri. Thanks a lot.
Ashik said:
1 decade ago
S.I for one yr=854-815=39
for 4 years=4*39=156
hence,854-156=698
i think it will be simple....
for 4 years=4*39=156
hence,854-156=698
i think it will be simple....
Vikram said:
1 decade ago
According to the question,
SI + P = 815 in three years and
SI + P = 854 in four years
so 815 - P = SI and
854 - P = SI
Therefore,
815 - P = (P * 3 * R)/100 and ---- eq 1
854 - P = (P * 4 * R)/100 ---- eq 2
Now,
eq 1 / eq 2 gives
(815 - P)/(854 - P) = 3/4
Solving this eq, we get
P = 698
SI + P = 815 in three years and
SI + P = 854 in four years
so 815 - P = SI and
854 - P = SI
Therefore,
815 - P = (P * 3 * R)/100 and ---- eq 1
854 - P = (P * 4 * R)/100 ---- eq 2
Now,
eq 1 / eq 2 gives
(815 - P)/(854 - P) = 3/4
Solving this eq, we get
P = 698
(1)
Uma said:
1 decade ago
@gayathri your explination is very helpfull.
Thank you.
Thank you.
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