Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 1)
1.
A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
Answer: Option
Explanation:
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
Discussion:
171 comments Page 13 of 18.
Imran syed said:
9 years ago
For simple interest, this formula is very helpful.
That is I = Prt.
That is I = Prt.
Sumair mudliar said:
9 years ago
@Md Sahil.
Thank you for explaining the solution.
Thank you for explaining the solution.
Naren said:
10 years ago
815-p = 3*x.1 -----> equation 1.
854-p = 4*x.2 -----> equation 2.
Divide equation 1 with equation 2.
854-p = 4*x.2 -----> equation 2.
Divide equation 1 with equation 2.
Md sahil said:
10 years ago
Sum amounts to 815 in 3 years.
Sum amounts to 854 in 4 years.
Find sum?
Let the sum be Rs. x.
x = principal amounts in 3 years = Rs. 815.
x = principal amounts in 4 years = Rs. 854.
Principal amount in 1 year = 39 I.
Interest of 1 year = Rs. 39.
Interest of 3 year = 3x39= Rs. 117.
Principal = x.
Rate = ?
Time = 3 years.
For 3 years.
Interest = Rs. 117.
Amount = Rs. 815.
Time = 3 years.
Let rate = R%.
A = p+I.
P = A-I.
= R(815-117).
Rate 698 answer.
Sum amounts to 854 in 4 years.
Find sum?
Let the sum be Rs. x.
x = principal amounts in 3 years = Rs. 815.
x = principal amounts in 4 years = Rs. 854.
Principal amount in 1 year = 39 I.
Interest of 1 year = Rs. 39.
Interest of 3 year = 3x39= Rs. 117.
Principal = x.
Rate = ?
Time = 3 years.
For 3 years.
Interest = Rs. 117.
Amount = Rs. 815.
Time = 3 years.
Let rate = R%.
A = p+I.
P = A-I.
= R(815-117).
Rate 698 answer.
Prasad said:
10 years ago
Will you elaborate it in understanding way?
Monika said:
10 years ago
Can explain me logic behind it?
ShamInzu said:
1 decade ago
3y---815.
4y---854.
------------
1y---39.
3y---39*3 = 117 or 4y---39*4 = 156.
815-117 = 698 or 854-156 = 698.
So we could subtract by 854 or 815.
All The best. Think smart.
4y---854.
------------
1y---39.
3y---39*3 = 117 or 4y---39*4 = 156.
815-117 = 698 or 854-156 = 698.
So we could subtract by 854 or 815.
All The best. Think smart.
Stuti said:
1 decade ago
Hi.
There is a simple shortcut for solving this question.
P/Sum = A1n2-A2n1/n2-n1.
= 815*4-854*3/4-3.
= 3260-2562/1 = 698.
There is a simple shortcut for solving this question.
P/Sum = A1n2-A2n1/n2-n1.
= 815*4-854*3/4-3.
= 3260-2562/1 = 698.
Magesh said:
1 decade ago
For four years the interest is,
854-815 = 39.
39*4 = 156.
So 854-156 = 698.
It may simple one no need to apply any formulas here. Time waste one.
854-815 = 39.
39*4 = 156.
So 854-156 = 698.
It may simple one no need to apply any formulas here. Time waste one.
Priyanka said:
1 decade ago
Hi friends.
Here goes the explanation,
SI for 4 years = Rs 854.
SI for 3 years = Rs 815.
{4-3} = 1.
So SI for 1 year can be {854-815}.
= Rs 39.
So the SI for 3 years can be {39*3}.
= 117.
So principal is 815-117.
= RS 698{ANS}.
Here goes the explanation,
SI for 4 years = Rs 854.
SI for 3 years = Rs 815.
{4-3} = 1.
So SI for 1 year can be {854-815}.
= Rs 39.
So the SI for 3 years can be {39*3}.
= 117.
So principal is 815-117.
= RS 698{ANS}.
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