Aptitude - Simple Interest - Discussion

Discussion Forum : Simple Interest - General Questions (Q.No. 1)
1.
A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
Rs. 650
Rs. 690
Rs. 698
Rs. 700
Answer: Option
Explanation:

S.I. for 1 year = Rs. (854 - 815) = Rs. 39.

S.I. for 3 years = Rs.(39 x 3) = Rs. 117.

Principal = Rs. (815 - 117) = Rs. 698.

Discussion:
171 comments Page 12 of 18.

Nirmala said:   8 years ago
Why we are not substructing 854? Please explain.

Manya said:   8 years ago
Thanks a lot @Gayatri.

Surjeet said:   8 years ago
Because we calculate with 3 years that is why we subtract from 815.

Anusha said:   8 years ago
Very helpful to understand the solution. Thanks for all your explanation.

Deepthy said:   8 years ago
Thanks @Pradeep.

Sunil said:   8 years ago
Thanks, I like this explanation.

This is helpful to understand the simple interest.

Pawan said:   8 years ago
How can we apply formula 100*SI/RT?

Here R is not given.

Marikkannan said:   8 years ago
Thanks for all the explanation. It is a very helpful solution.

Ashwini said:   8 years ago
A2T1-A1T2/T1-T2.

The above formula is applies here,
854 * 3-815 * 4/3-4,
2562-3260/-1,
= 698.

AMAN said:   8 years ago
Hi, I cannot understand one thing that how could be the amount increasing every year is constant?

I mean if suppose 100 is the principle and rate is 10 percent then for the first year the amount will be 110, 2nd year it will be 121, 3rd year it will be 133.10.

Now 133.1 -121 is not equal to 121-110 also not equal to 110 -100 so the increasing amount is not constant. In this problem, how can we take the increasing amount constant and directly subtract it and divide it?

I mean how is it possible that the increasing amount remains 39 over three years?


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