Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 3)
3.
A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum?
Answer: Option
Explanation:
| Principal |
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| = Rs. 8925. |
Discussion:
62 comments Page 2 of 7.
Anonymous said:
4 years ago
PCPA is used for compound interest. Right?
(3)
Narendra ahirwar said:
6 years ago
Given:
s.i. =4016.25.
r=9,
t=5 y.
p = (100*s.i.)/r*t.
= 100*4016.25/9*5,
= 401625/45,
= 8925 ans.
s.i. =4016.25.
r=9,
t=5 y.
p = (100*s.i.)/r*t.
= 100*4016.25/9*5,
= 401625/45,
= 8925 ans.
(3)
Parkash jha said:
8 years ago
5 years = 4016.25.
So, 1 years = 803.25.
Now formula, Rate % = Interest/principalx100(only for 1 years).
So, principal=803.25/9x100=8925.
Hence principal = 8925 ans=(C).
So, 1 years = 803.25.
Now formula, Rate % = Interest/principalx100(only for 1 years).
So, principal=803.25/9x100=8925.
Hence principal = 8925 ans=(C).
(1)
Karthick said:
6 years ago
Why we take 100?
I can't understand this problem. Please anyone explain this problem.
I can't understand this problem. Please anyone explain this problem.
(1)
Bhavna said:
1 decade ago
@Fortune.
We know that P = S.I*100/R*T.
Given S.I = 4016.25, R = 9, T = 5.
Substitute these values in above formula,
Then,
P = 4016.25*100/9*5.
P = 4016.25*20/9 (Cancel 100 with 5).
P = 80325/9.
By simplifying this we get.
P = Rs.8925.
Hope it is understandable.
We know that P = S.I*100/R*T.
Given S.I = 4016.25, R = 9, T = 5.
Substitute these values in above formula,
Then,
P = 4016.25*100/9*5.
P = 4016.25*20/9 (Cancel 100 with 5).
P = 80325/9.
By simplifying this we get.
P = Rs.8925.
Hope it is understandable.
(1)
Tahir Qureshi said:
2 months ago
Total simple interest is 4016.25.
Collect in 5years.
At a Rate of 9%p.a.
then SI =4016.25.
Rate = 9 * 5 = 45%.
Now, 4016.25/45 * 100.
= 401625/45.
= 8925.
Collect in 5years.
At a Rate of 9%p.a.
then SI =4016.25.
Rate = 9 * 5 = 45%.
Now, 4016.25/45 * 100.
= 401625/45.
= 8925.
(1)
Lakshmi said:
9 years ago
I understand your concept thanks @Bhavna.
Faustina paradise said:
8 years ago
We can also use the formula.
Simple interest =principal *rate *time all over 100.
4016.25=p*9*5/100,
4016.25=45p/100,
Then cross multiply;
45p=401625,
divid both side by 45.
p=8925.
There the sum = 8925.
Simple interest =principal *rate *time all over 100.
4016.25=p*9*5/100,
4016.25=45p/100,
Then cross multiply;
45p=401625,
divid both side by 45.
p=8925.
There the sum = 8925.
Vinaya said:
8 years ago
Hi friends! I am Vinaya.
Here we have to find d sum(p).
So formula we know is S.I=P*R*T/100;.
SO, p=S.I*100/R*T--->given S.I=4016.25 we can write it as 401625/100...R=9,T=5.
Substitute the values ...P=401625*100/100*9*5..
After calculation, we get 8925.
Here we have to find d sum(p).
So formula we know is S.I=P*R*T/100;.
SO, p=S.I*100/R*T--->given S.I=4016.25 we can write it as 401625/100...R=9,T=5.
Substitute the values ...P=401625*100/100*9*5..
After calculation, we get 8925.
Vineeth said:
8 years ago
A=p(1+RT/100).
A=total money, borrow,
P=lended,loan,sum,
R=rate,
T=time.
A=total money, borrow,
P=lended,loan,sum,
R=rate,
T=time.
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