Aptitude - Simple Interest - Discussion

Discussion Forum : Simple Interest - General Questions (Q.No. 3)
3.
A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum?
Rs. 4462.50
Rs. 8032.50
Rs. 8900
Rs. 8925
None of these
Answer: Option
Explanation:
Principal
= Rs. 100 x 4016.25
9 x 5
= Rs. 401625
45
= Rs. 8925.
Discussion:
62 comments Page 2 of 7.

Anonymous said:   4 years ago
PCPA is used for compound interest. Right?
(3)

Narendra ahirwar said:   6 years ago
Given:
s.i. =4016.25.
r=9,
t=5 y.

p = (100*s.i.)/r*t.
= 100*4016.25/9*5,
= 401625/45,
= 8925 ans.
(3)

Parkash jha said:   8 years ago
5 years = 4016.25.
So, 1 years = 803.25.

Now formula, Rate % = Interest/principalx100(only for 1 years).
So, principal=803.25/9x100=8925.

Hence principal = 8925 ans=(C).
(1)

Karthick said:   6 years ago
Why we take 100?

I can't understand this problem. Please anyone explain this problem.
(1)

Faustina paradise said:   8 years ago
We can also use the formula.

Simple interest =principal *rate *time all over 100.
4016.25=p*9*5/100,
4016.25=45p/100,
Then cross multiply;
45p=401625,
divid both side by 45.
p=8925.
There the sum = 8925.

Vinaya said:   8 years ago
Hi friends! I am Vinaya.

Here we have to find d sum(p).
So formula we know is S.I=P*R*T/100;.
SO, p=S.I*100/R*T--->given S.I=4016.25 we can write it as 401625/100...R=9,T=5.
Substitute the values ...P=401625*100/100*9*5..

After calculation, we get 8925.

Sunita balami said:   6 years ago
S.I = PTR/100.

Vineeth said:   8 years ago
A=p(1+RT/100).

A=total money, borrow,
P=lended,loan,sum,
R=rate,
T=time.

Shahi Fazal said:   8 years ago
Total S.I-Rs4016.25.
Rate-9%
Time-5yrs
S.I.=[P*R*T/100]
So,
P=[S.I.*100/R*T]
P=[4016.25*100/9*5]
=8925 Ans.

NEELESH said:   8 years ago
HERE IS AN INTERESTING TRICK:

Since, the rate is 9% for 5 years, so total SI is 45%.

Now 45% = 4016.25 so 100% = 4016.25*100/45 = 8925.


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