Aptitude - Ratio and Proportion - Discussion

Let their Ratio = 5X,2X,4X,3X.
C+1000 = D
C-D = 1000,
4X-3X = 1000,
X = 1000,
B = 2X = 2.1000=2000.

The question that means if c gets 1000 more than d and this is a keyword.

That's while: c refers as 4x and d refers as 3x. which means 4x + 1000=3x

=> 4x-3x=1000
X=1000.

Thereby sub x=1000 in all term,
5x=5000 as A share,
2x=2000 as B share,
4x=4000as C share,
And 3x=3000 as D share.

A:B:C:D= 5:2:4:3.

A's money share = 5x
B's money share = 2x
C's money share = 4x
D's money share = 3x.

C get 1000 more than D.

C's money= D's money + 1000,
4x= 3x + 1000,
4x-3x = 1000,
X = 1000.

B's money share=2x,
= 2 * 1000,
= 2000.

Simple way to solve:

A : B : C : D = 5 : 2 : 4 : 3.

In this ratio, B's value =2.

B's share =1000(given) * 2 = 2000(option c).

@Santosh, Money is not equally distributed that is already given in question. Are you have some difficulty understanding this 5x thing?

In the question he didn't mention that money is equally distributed, so how could all take it as var x for all?

@All.

According to me;
From the question; C gets 1000 more than D.
Hence C= 1000+D --> (1)
Now from the proportion given, A:B:C:D is equal to 5:2:4:3.
We can then say C:D = 4:3.
or C/D = 4/3 ---> (2)

Put equation (1) into (2)
4/3 = (1000 +D)/ D (using change of subject D= 3000).

Remember the unknown is B.
hence utilizing the proportion with the known values:
2:4 = B: C.
2/4 = B/(1000+3000) NB: c= 1000 +D from equation 1.

Thus using a change of subject B = 2000.

How to solve this problem? Please help me.

Divide rupees 500 between A, B and C so that A gets 2/3 of what B gets and B gets 1/4 of what C gets. Find the share of each.

According to the given solution that;

3x+1000=4x but x =2000 but it doesn't satisfy this equation.

Thanks every one.

The simplest solution I found is;

a:b:c:d
5:2:4:3
let the amounts be;
5x,2x,4x, and 3x respectively.

then according to the condition.
1000=c-d.
1000=4x-3x.
1000=1x.

Since;
b=2x.
Therefore.
b=2(1000),
b=2000.