Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 6)
6.
The ratio of the number of boys and girls in a college is 7 : 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio?
Answer: Option
Explanation:
Originally, let the number of boys and girls in the college be 7x and 8x respectively.
Their increased number is (120% of 7x) and (110% of 8x).
 |
 |
120 | x 7x |  |
and | |
110 | x 8x | |
| 100 | 100 |
| |
42x | and | 44x |
| 5 | 5 |
 The required ratio = |
|
42x | : | 44x | |
= 21 : 22. |
| 5 | 5 |
Discussion:
63 comments Page 7 of 7.
Paras said:
4 months ago
Let's suppose.
Total 15* 10 = 150
Boys 70
And girls 80.
20% of boys = 14 + 70 = 84.
10% of girls = 80 + 10 = 88.
84:88 divided by 2.
And the Answer is 21:22.
Total 15* 10 = 150
Boys 70
And girls 80.
20% of boys = 14 + 70 = 84.
10% of girls = 80 + 10 = 88.
84:88 divided by 2.
And the Answer is 21:22.
(1)
SAI PRASANNA said:
3 months ago
42/5:88/10.
88/10 is equal to 44/5.
Now,
42/5:44/5.
Denominators are equal. So,
42:44.
By reducing ,we get,
21:22.
88/10 is equal to 44/5.
Now,
42/5:44/5.
Denominators are equal. So,
42:44.
By reducing ,we get,
21:22.
(1)
Tanu said:
1 week ago
Boys 7 = 20%.
Girls 8 = 10%.
120/ 100 = 1.2x7 = 84
110/ 100 = 1.1x8 = 88.
Here (boys& girls) so divided by 2.
84/2 = 42
88/2 = 44.
Again divided by 2.
42/2=21
44/2=22
So, new ratio = 21:22.
Girls 8 = 10%.
120/ 100 = 1.2x7 = 84
110/ 100 = 1.1x8 = 88.
Here (boys& girls) so divided by 2.
84/2 = 42
88/2 = 44.
Again divided by 2.
42/2=21
44/2=22
So, new ratio = 21:22.
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