Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 9)
9.
The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
Answer: Option
Explanation:
Let the three parts be A, B, C. Then,
| A : B = 2 : 3 and B : C = 5 : 8 = | ![]() |
5 x | 3 | ![]() |
: | ![]() |
8 x | 3 | ![]() |
= 3 : | 24 |
| 5 | 5 | 5 |
A : B : C = 2 : 3 : |
24 | = 10 : 15 : 24 |
| 5 |
B = |
![]() |
98 x | 15 | ![]() |
= 30. |
| 49 |
Discussion:
123 comments Page 13 of 13.
Kishore said:
12 months ago
2 : 3 : same as second (3).
same as second (5) : 5 : 8.
2*5 = 10 || 3*5 = 15 || 3*8 = 24,
Combined ratio: 10:15:24.
The Sum of ratios: 10+15+24 = 49.
Actual sum: 98.
Multiply by 2: 10×2=20, 15×2=30, 24×2=48.
Second number: 30.
same as second (5) : 5 : 8.
2*5 = 10 || 3*5 = 15 || 3*8 = 24,
Combined ratio: 10:15:24.
The Sum of ratios: 10+15+24 = 49.
Actual sum: 98.
Multiply by 2: 10×2=20, 15×2=30, 24×2=48.
Second number: 30.
(8)
Preethi said:
9 months ago
A : B = 2 : 3
B:C = 5:8
Given, A + B + C = 98.
A : B = 2 : 3
B : C = 5 : 8
Now, A : B : C = (2 * 5) : (5 * 3) : (3 * 8),
= 10 : 15 : 24.
The sum of these numbers is 49 which is not equal to 98. So multiple ratio with 2.
(10 : 15 : 24) * 2 = 20 : 30 : 48.
The sum of these numbers is 98.
Therefore 2nd number is 30.
B:C = 5:8
Given, A + B + C = 98.
A : B = 2 : 3
B : C = 5 : 8
Now, A : B : C = (2 * 5) : (5 * 3) : (3 * 8),
= 10 : 15 : 24.
The sum of these numbers is 49 which is not equal to 98. So multiple ratio with 2.
(10 : 15 : 24) * 2 = 20 : 30 : 48.
The sum of these numbers is 98.
Therefore 2nd number is 30.
(34)
Jatin said:
1 month ago
Let,
X + Y + Z = 98 ---> (1)
X : Y = 2 : 3.
Then,
X/Y=2/3 =>3X=2Y
=> X = 2y/3 ---> (2)
Y:Z=5:8
then,
Y/Z=5/8 =>5Y=8Z =>z=5Y/8 ---> (3)
putting values of (2)&(3) in (1)
X + Y + Z = 98,
2Y/3 + Y + 8Y/5 = 98,
10Y + 15Y + 24Y/15 = 98,
49Y = 98*15,
Y = 1470/49,
Then Y = 30.
X + Y + Z = 98 ---> (1)
X : Y = 2 : 3.
Then,
X/Y=2/3 =>3X=2Y
=> X = 2y/3 ---> (2)
Y:Z=5:8
then,
Y/Z=5/8 =>5Y=8Z =>z=5Y/8 ---> (3)
putting values of (2)&(3) in (1)
X + Y + Z = 98,
2Y/3 + Y + 8Y/5 = 98,
10Y + 15Y + 24Y/15 = 98,
49Y = 98*15,
Y = 1470/49,
Then Y = 30.
(5)
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A : B : C = 2 : 3 :