Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 2)
2.
A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is:
Answer: Option
Explanation:
A's speed = | ![]() |
5 x | 5 | ![]() |
= | 25 | m/sec. |
18 | 18 |
Time taken by A to cover 100 m = | ![]() |
100 x | 18 | ![]() |
= 72 sec. |
25 |
Time taken by B to cover 92 m = (72 + 8) = 80 sec.
![]() |
![]() |
92 | x | 18 | ![]() |
= 4.14 kmph. |
80 | 5 |
Discussion:
29 comments Page 1 of 3.
Manikanta said:
6 years ago
Here A runs for 100meters while B has to run only for 92Meters as B is 8meters ahead of A.
5km per hour=5000 meters per hour.
As the question is asking in seconds. Now convert for each second how many meters A is running.
Here we have 3600 seconds for one hour.
So 5000meters or 5*1000meters/3600 which comes to 5*5/18=25/18.
In how many seconds A ran the100meters =100m*25/18sec=72sec.
A has run 8seconds faster than B. Which means B took 8seconds more to complete the run. Therefore 72+8=80Sec.
Now the question is B's speed in km per hour.
Calculate for each sec how many meters he ran=92meters/80sec.
Hence=92/80*18/5 (lets say 3600sec/1000meters) =4.14kmph.
5km per hour=5000 meters per hour.
As the question is asking in seconds. Now convert for each second how many meters A is running.
Here we have 3600 seconds for one hour.
So 5000meters or 5*1000meters/3600 which comes to 5*5/18=25/18.
In how many seconds A ran the100meters =100m*25/18sec=72sec.
A has run 8seconds faster than B. Which means B took 8seconds more to complete the run. Therefore 72+8=80Sec.
Now the question is B's speed in km per hour.
Calculate for each sec how many meters he ran=92meters/80sec.
Hence=92/80*18/5 (lets say 3600sec/1000meters) =4.14kmph.
(1)
Vinay said:
10 years ago
We have given speed of A = 5 km/h => 5x5/18 = (25/18) speed;
A takes time = 100x (18/25), Time = Distance/Speed;
=72 sec;
Since A beat B by 8 sec.
So total time taken by B = 72+8 = 80 (time);
Since A gives 8 m to B.
So total distance cover by B = 100-8 = 92 (dist);
We know that Speed = Distance/Time;
Now speed of B = 92/80 m/s;
Now converting it into km/h => (92/80) x (18/5).
=> 4.4 answer.
A takes time = 100x (18/25), Time = Distance/Speed;
=72 sec;
Since A beat B by 8 sec.
So total time taken by B = 72+8 = 80 (time);
Since A gives 8 m to B.
So total distance cover by B = 100-8 = 92 (dist);
We know that Speed = Distance/Time;
Now speed of B = 92/80 m/s;
Now converting it into km/h => (92/80) x (18/5).
=> 4.4 answer.
Qwaci said:
1 decade ago
@ Sag & Mangesh.
First of all, A gave B a start of 8m so B did not run 100m but 92m (100m-8m). Secondly, A took 72sec to cover the 100m and still won B who had only 92m to run by 8sec which means that with the 92m that B covered he used or needed 80sec (72sec+8sec). I hope my little explanation could help you understand.
First of all, A gave B a start of 8m so B did not run 100m but 92m (100m-8m). Secondly, A took 72sec to cover the 100m and still won B who had only 92m to run by 8sec which means that with the 92m that B covered he used or needed 80sec (72sec+8sec). I hope my little explanation could help you understand.
(1)
Padma said:
1 decade ago
Here first we can find the losers time, secondly we can find losers distance[since losers distance=winners distance- (start distance+beat distance) ] and later we can find the speed of B[since speed=distance/time]. Which is the final answer.
Is this not the correct procedure. Please tell me if it is.
Is this not the correct procedure. Please tell me if it is.
Prafull gadekar said:
1 decade ago
Instead of taking 5/18, we solve like,
A 's speed = 5 kmph = 5000 mph = 5000/3600 = 1.38m/sec,
For 100m distance time = 72.3 sec or 72 sec,
B's require time to cover 92m distance=(72+8) = 80 sec.
80 sec- 92m then,
1 sec - 1.15m.
1.15m/sec.
1.15*3600 = 4140 mph = 4.14 kmph.
A 's speed = 5 kmph = 5000 mph = 5000/3600 = 1.38m/sec,
For 100m distance time = 72.3 sec or 72 sec,
B's require time to cover 92m distance=(72+8) = 80 sec.
80 sec- 92m then,
1 sec - 1.15m.
1.15m/sec.
1.15*3600 = 4140 mph = 4.14 kmph.
(3)
Girijesh said:
1 decade ago
Let speed of B is x meter/sec.
Speed of A is y meter/sec.
Total time to reach 100 meter by A is 100m/5kmph = 72 sec.
Total time to reach 100 meter by B is:
(8/x) + time taken by A + 8 = 100/x.
(8/x) + 72 + 8 = 100/x.
x = 92/80 m/s = 4.14 kmph.
Speed of A is y meter/sec.
Total time to reach 100 meter by A is 100m/5kmph = 72 sec.
Total time to reach 100 meter by B is:
(8/x) + time taken by A + 8 = 100/x.
(8/x) + 72 + 8 = 100/x.
x = 92/80 m/s = 4.14 kmph.
(1)
Sudharshan madgula said:
1 decade ago
@Baburaj:
Because A is taking 72sec to run 100m and beats B by 8sec.
that means still B needs 8sec to complete 100m.
therefore time taken by B to complete 92m is 72+8=80sec.
Because A is taking 72sec to run 100m and beats B by 8sec.
that means still B needs 8sec to complete 100m.
therefore time taken by B to complete 92m is 72+8=80sec.
Sairam said:
6 years ago
Actually, B has to complete 92 meters in 72 seconds but he is taking an extra 8 seconds time to complete 100 meters which can be concluded from the question. Am I right?
(3)
Sanju said:
1 decade ago
Out of 100m he ran 8m so we deduct 8m from 100m then we get 92m to obtain B Speed we should caluclate B Speed by using 92m instead of 100m. I hope you understand. !
Buddhika said:
1 decade ago
Forget 5 kmh.
A runs = 8 m.
B runs = 100-8 = 92 m.
B speed = 92 m/8 s = 11.5 ms.
Now we convert ms = kmh.
11.5 x 18/5 = 4.14 kmh.
That is all.
A runs = 8 m.
B runs = 100-8 = 92 m.
B speed = 92 m/8 s = 11.5 ms.
Now we convert ms = kmh.
11.5 x 18/5 = 4.14 kmh.
That is all.
(2)
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