Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 4)
4.
In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:
Answer: Option
Explanation:
A : B = 100 : 90.
A : C = 100 : 87.
| B | = | B | x | A | = | 90 | x | 100 | = | 30 | . |
| C | A | C | 100 | 87 | 29 |
When B runs 30 m, C runs 29 m.
| When B runs 180 m, C runs |  |
29 | x 180 |  m |
= 174 m. |
| 30 |
B beats C by (180 - 174) m = 6 m.
Discussion:
13 comments Page 2 of 2.
Pintu kashyap said:
1 decade ago
If say answer is 5.4 means we are including A also in the race but qtn asking about B & C.
In 100m race B cover 90m and c cover 87m. In another 90m B also cover 90m and c cover 87.
Total a cover 180m and c cover 174. So 180-172 = 6 m.
In 100m race B cover 90m and c cover 87m. In another 90m B also cover 90m and c cover 87.
Total a cover 180m and c cover 174. So 180-172 = 6 m.
Rohit said:
1 decade ago
Hi friends i got the simple method
when A complete 100 m then
B (100-10)=90
and c (100-13)=87
they ask in 180m race B beat c means
if B covers 180 which is twice of 90
then C will reach 87*2 = 174
180-174=6
when A complete 100 m then
B (100-10)=90
and c (100-13)=87
they ask in 180m race B beat c means
if B covers 180 which is twice of 90
then C will reach 87*2 = 174
180-174=6
(3)
Tarun gupta said:
1 decade ago
I am getting 5.4 as answer. Please help.
if A runs 180 then b runs 162 (90*180/100)
if A runs 180 then C runs 156.6(87*180/100)
Difference=5.4
What is wrong in my approach. Help ?
if A runs 180 then b runs 162 (90*180/100)
if A runs 180 then C runs 156.6(87*180/100)
Difference=5.4
What is wrong in my approach. Help ?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers