Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 1)
1.
In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:
Answer: Option
Explanation:
A : B = 100 : 90.
A : C = 100 : 72.
B : C = | B | x | A | = | 90 | x | 100 | = | 90 | . |
A | C | 100 | 72 | 72 |
When B runs 90 m, C runs 72 m.
When B runs 100 m, C runs | ![]() |
72 | x 100 | ![]() |
= 80 m. |
90 |
B can give C 20 m.
Discussion:
43 comments Page 5 of 5.
Aakriti said:
9 years ago
Thanks, @Abhishek Kushwaha.
Saru said:
1 decade ago
Why we use B/AxA/c here?
Diya said:
1 decade ago
It is meter.
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