Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 3)
3.
In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by:
Answer: Option
Explanation:
To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.
While A covers 3 m, B covers 4 m.
| While A covers 360 m, B covers |  |
4 | x 360 |  m |
= 480 m. |
| 3 |
Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.
A wins by 20 m.
Discussion:
14 comments Page 2 of 2.
Anand said:
6 years ago
Here is the simplest method,
Speed ratio is 3:4 SO let consider 3m & 4m for both A & B.
A travels 360 and B travels 500.
This means A takes 120 seconds and B takes 125 seconds.
5 seconds more than A is travelled by B.
In one B travels 4m.
So in 5 seconds, 5*4=20m.
B travels 20m more than A.
That is A win by 20m.
Speed ratio is 3:4 SO let consider 3m & 4m for both A & B.
A travels 360 and B travels 500.
This means A takes 120 seconds and B takes 125 seconds.
5 seconds more than A is travelled by B.
In one B travels 4m.
So in 5 seconds, 5*4=20m.
B travels 20m more than A.
That is A win by 20m.
(4)
BKD said:
5 years ago
3/4 = (500-140)/x.
x = 480.
Thus, In 500 m race, A gives B by 20m i.e.500-480.
x = 480.
Thus, In 500 m race, A gives B by 20m i.e.500-480.
(1)
ANUPCHERRY said:
4 years ago
A : B =140M.
3X + 4X =7X,
140/7 = 20M.
3X + 4X =7X,
140/7 = 20M.
(8)
Yadu said:
3 years ago
How come we take 3 as 3m and 4 as 4m If time is not a constant here?
Anyone, explain to me.
Anyone, explain to me.
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