Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 7)
7.
In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:
Answer: Option
Explanation:
| Distance covered by B in 9 sec. = |  |
100 | x 9 |  m |
= 20 m. |
| 45 |
A beats B by 20 metres.
Discussion:
13 comments Page 2 of 2.
Himanshu Singla said:
1 decade ago
Here it is given that A can cover 100m in 36 sec and B in 45 sec. So when A reaches finish point B still has 9 sec left of his time to reach the final point. In this time he can cover the remaining distance by which he has been beaten.
In 45sec B can travel 100m.
In 1sec ------------- 100/45.
In 9 sec ------------ (100/45) *9=20 Answer.
HOPE you UNDERSTAND. Please clarify if am wrong.
In 45sec B can travel 100m.
In 1sec ------------- 100/45.
In 9 sec ------------ (100/45) *9=20 Answer.
HOPE you UNDERSTAND. Please clarify if am wrong.
Gowthami said:
1 decade ago
A beats=36sec
B beats=45sec
so 36----45
then 1 part=45/36=5/4
B covers A in 100m race=(4/5)*100=80m
so A beats B by=(total distance)100-B covers(80)
20m faster than B
B beats=45sec
so 36----45
then 1 part=45/36=5/4
B covers A in 100m race=(4/5)*100=80m
so A beats B by=(total distance)100-B covers(80)
20m faster than B
Muneer said:
1 decade ago
Why we are taking 45 in the solution?
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