Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 7)
7.
In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:
Answer: Option
Explanation:
| Distance covered by B in 9 sec. = |  |
100 | x 9 |  m |
= 20 m. |
| 45 |
A beats B by 20 metres.
Discussion:
13 comments Page 1 of 2.
Muneer said:
1 decade ago
Why we are taking 45 in the solution?
Gowthami said:
1 decade ago
A beats=36sec
B beats=45sec
so 36----45
then 1 part=45/36=5/4
B covers A in 100m race=(4/5)*100=80m
so A beats B by=(total distance)100-B covers(80)
20m faster than B
B beats=45sec
so 36----45
then 1 part=45/36=5/4
B covers A in 100m race=(4/5)*100=80m
so A beats B by=(total distance)100-B covers(80)
20m faster than B
Himanshu Singla said:
1 decade ago
Here it is given that A can cover 100m in 36 sec and B in 45 sec. So when A reaches finish point B still has 9 sec left of his time to reach the final point. In this time he can cover the remaining distance by which he has been beaten.
In 45sec B can travel 100m.
In 1sec ------------- 100/45.
In 9 sec ------------ (100/45) *9=20 Answer.
HOPE you UNDERSTAND. Please clarify if am wrong.
In 45sec B can travel 100m.
In 1sec ------------- 100/45.
In 9 sec ------------ (100/45) *9=20 Answer.
HOPE you UNDERSTAND. Please clarify if am wrong.
Marimuthu said:
1 decade ago
In 36 seconds B covers (100/45)*36 = 80 meters.
In 36 seconds A covers 100 meters.
So A beat B by 20 meters.
In 36 seconds A covers 100 meters.
So A beat B by 20 meters.
Mridul Chakraborty said:
1 decade ago
Detailed solution for easier interpretation :
Speed of A = 100 (distance)/36 (Time) = 2.78 m/s.
Speed of B = 100(distance)/45(Time) = 2.22 m/s.
Difference in speed between A & B = 0.56 m/s < i.e. 2.78-2.22 m/s>
Hence in 36 seconds in which A finishes the race, B will cover 2.22*36 = 80 meters.
So A finishes the race 20m ahead of B.
Speed of A = 100 (distance)/36 (Time) = 2.78 m/s.
Speed of B = 100(distance)/45(Time) = 2.22 m/s.
Difference in speed between A & B = 0.56 m/s < i.e. 2.78-2.22 m/s>
Hence in 36 seconds in which A finishes the race, B will cover 2.22*36 = 80 meters.
So A finishes the race 20m ahead of B.
NoName said:
9 years ago
A 1sec - (100/36) m.
B 1sec - (100/45) m.
1sec - A is ahead by (100/36-100/45) = 5/9 m.
So, in 36s A is ahead by (5/9*36) = 20 m.
B 1sec - (100/45) m.
1sec - A is ahead by (100/36-100/45) = 5/9 m.
So, in 36s A is ahead by (5/9*36) = 20 m.
Santhosh said:
8 years ago
36/45*100 = 80.
100-80 = 20.
100-80 = 20.
Student said:
8 years ago
That's a great help thanks a lot!
T.somadatta said:
6 years ago
Speed of A = 100 (distance) /36 (Time) = 2.78 m/s.
Speed of B = 100 (distance) /45 (Time) = 2.22 m/s.
Difference in speed between A & B = 0.56 m/s < i.e. 2.78-2.22 m/s>.
Hence in 36 seconds in which A finishes the race, B will cover 2.22*36 = 80 meters.
So, A finishes the race 20m ahead of B.
Speed of B = 100 (distance) /45 (Time) = 2.22 m/s.
Difference in speed between A & B = 0.56 m/s < i.e. 2.78-2.22 m/s>.
Hence in 36 seconds in which A finishes the race, B will cover 2.22*36 = 80 meters.
So, A finishes the race 20m ahead of B.
Sana said:
6 years ago
Common time difference between A and B is =(45-36)=9sec.
Now, B travel distance 100m in 45sec.
So
45sec ----------> 100m
9sec ------------> (9/45)*100=20m.
This 20m is actual distance between A and B or A beat by B in 20m .
Now, B travel distance 100m in 45sec.
So
45sec ----------> 100m
9sec ------------> (9/45)*100=20m.
This 20m is actual distance between A and B or A beat by B in 20m .
(1)
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