Aptitude - Profit and Loss - Discussion

Discussion Forum : Profit and Loss - Data Sufficiency 4 (Q.No. 1)
Directions to Solve

Each of these questions is followed by three statements. You have to study the question and all the three statements given to decide whether any information provided in the statement(s) is redundant and can be dispensed with while answering the given question.


1.

What is the percent profit earned by the shopkeeper on selling the articles in his shop?

I. 

Labeled price of the articles sold was 130% of the cost price.

II. 

Cost price of each article was Rs. 550.

 III. 

A discount of 10% on labeled price was offered.

Only I
Only II
I and III
All the three are required
Question cannot be answer even with information in all the three statements.
Answer: Option
Explanation:

  I. Let C.P. be Rs. x.

Then, M.P. = 130% of x = Rs. 13x .
10

III. S.P. = 90% of M.P.

Thus, I and III give, S.P. = Rs. 90 x 13x = Rs. 117x
100 10 100

Gain = Rs. 117x - x = Rs. 17x
100 100

Thus, from I and III, gain % can be obtained.

Clearly, II is redundant.

Discussion:
25 comments Page 3 of 3.

Chandra shekar said:   1 decade ago
I'm getting confused always, dozens, quantal, real etc, please give the details for that sir.

Shikha said:   1 decade ago
But to find out p% we require cp.

Vicky said:   1 decade ago
I agree with this

Showry said:   1 decade ago
hey guys what i think is........All the three are required

1)L.P=130% of C.P ==> L.P=[(100+130)/100]* c.p

2)c.p=550.rs L.p= (230/100)*550.....L.P=1265.rs

3)10% discount on L.P..... So,
lets take L.p as C.P to find loss

10=(loss*100)/1265....

and loss=126.5 rs

Now Article actually sold at S.P= L.P-loss

S.P =1265-126.50
S.P= 1138.50 rs
But Profit %?????????????????

C.P=550 & S.P=1138.50 Profit= 588.50

P % = (588.50*100)/550
P%=17%
----------------------------------------------------------------

Giriganesh said:   2 decades ago
This is not easy, pls anybody explain me?


Post your comments here:

Your comments will be displayed after verification.