Aptitude - Profit and Loss - Discussion

Discussion Forum : Profit and Loss - General Questions (Q.No. 6)
6.
The percentage profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280. At what price should the article be sold to make 25% profit?
Rs. 2000
Rs. 2200
Rs. 2400
Data inadequate
Answer: Option
Explanation:

Let C.P. be Rs. x.

Then, 1920 - x x 100 = x - 1280 x 100
x x

1920 - x = x - 1280

2x = 3200

x = 1600

Required S.P. = 125% of Rs. 1600 = Rs. 125 x 1600 = Rs 2000.
100

Video Explanation: https://youtu.be/0tTd5TwCspY

Discussion:
93 comments Page 8 of 10.

Shubham singh said:   7 years ago
So in this question Sp is given;

Sp=1920
Sp=1280

Now as per the given question:
percentage profit=percentage loss;
Sp - profit= Sp + loss.
1920-x=1280+x,
2 x=640,
x=320.

And now we have to find Sp at which article was sold.
Sp= (100+(p)%)/100) * C p.
For this we have to find Cp.
C p= Sp - profit.
= 1920-320,
= 1600.

Now we put this CP in to the above formula:

= ((100+25)/100) * 1600.
= (125/100) * 1600,
= 2000.

Ameer said:   6 years ago
Thanks @Shubham Singh.

Govinda said:   6 years ago
Let c.p=x.
p=1920-x.
l=x-1280.

As we know p% = l%.
1920-x=x-1280.
x=1600.
to get profit 25%.
1600+1600*25%.
----->2000.

Mohan reddy said:   6 years ago
In question, they have given that,

The percentage of profit earned by selling an article for Rs. 1920 is equal to the percentage loss incurred by selling the same article for Rs. 1280.

Now profit% = loss%.
From formula profit% = (s.p-c.p/c.p) *100.
Loss% = (c.p-s.p/c.p) *100.

Now equating both from given question,

(s.p-c.p/c.p) * 100 = (c.p-s.p/c.p) *100.

Now by cancelling 100 and c.p.

By substituting s.p values in above formula
1920 - c.p = c.p-1280,
2c.p = 3200.
c.p = 1600.

Now
profit%=(s.p-c.p/c.p) *100,
25=(s.p-1600/1600) *100,
Now after calculation s.p=2000.
Hope this will be helpful.

Mohd Faiq said:   6 years ago
@All

We can also solve this method:

SP1= 1920 , SP2=1280.
let profit % = loss% = x.

CP1= 100*1920 /(100+x).
CP2= 100*1280 /(100-x).

CP1=CP2
100*1920 /(100+x) = 100*1280 /(100-x)
x=20 = profit% = loss%.

CP= 100*1920 /(100+20) [on putting the value of x].
CP=1600.

New SP= (100+25)*1600 / 100,
New SP=1600.

Nalla peru said:   6 years ago
Explain this question properly.
(2)

Deepa sri said:   5 years ago
Easy explanation:

Let C.P=x,
Profit=s.p-c.p
=1920-x
Loss=c.p-s.p
=X-1280.

Then,
Profit%=profit/c.p*100
=((1920-x)/x)*100
Loss%=loss/c.p*100
=((x-1280)/x)*100
Profit%=loss%.

By equating the two,
((1920-x)/x)*100=((x-1280)/x)*100
1920-x=x-1280
2x=3200
x=1600.

Therefore, C.P=1600.
Now,the formula,
S.P=((100+profit%)/100)*C.P.
In que ,profit%=25%.
S.P=((100+25)/100)*1600.
=(125/100)*1600
= 2000.
I hope you all understand.

Avaneet Agrahari said:   5 years ago
According to me, the solution is;
1920 - 1280 = 640,
Gain% = loss%,
So, 320=320,
320 + 320 = 640,
CP = 1920 - 320 = 1600,
SP = (1600 * 25/100 + 1600) = 2000.

Subhojit said:   5 years ago
CP = (1920 + 1280)/2.
= 1600.

SP = (CP+profit).
= [1600 + {1600*(25/100)}],
= 1600 + 400,
= 2000.
(3)

Saifan said:   5 years ago
since profit(P) and loss(L) percentages are same:
=> P% = L% => P = L .
S.P for P% =1920 ; S.P for L% = 1280
=> 2P =2L = 1920 -1280 = 640
=> P = L = 320
Therefore C.P = S.P(p) - P = S.P(l) + L = 1600

new selling price for 25% profit will be
S.P = ((100 + P) / 100) * C.P = ((100 + 25) / 100) * 1600
= 125/100 * 1600
= 2000
(1)


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