Aptitude - Profit and Loss - Discussion
Discussion Forum : Profit and Loss - General Questions (Q.No. 4)
4.
In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
Answer: Option
Explanation:
Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. = Rs. 420.
New C.P. = 125% of Rs. 100 = Rs. 125
New S.P. = Rs. 420.
Profit = Rs. (420 - 125) = Rs. 295.
 Required percentage = |
 |
295 | x 100 |  % |
= | 1475 | % = 70% (approximately). |
| 420 | 21 |
Video Explanation: https://youtu.be/bQA8SB8ycbw
Discussion:
146 comments Page 4 of 15.
Sourav said:
6 years ago
%p = {(sp-cp)/cp} * 100.
Avinash reddy said:
6 years ago
Thanks for giving the solution @Anjali K.
Vaishnavi said:
6 years ago
Assume:
C. P=x.
S. P=2x.
Profit=3x.
Now,
Profit = ( sp-cp).
= 2x-x = x.
Now.
Profit% = cp/profit * 200.
=x\x * 100= 100.
C. P=x.
S. P=2x.
Profit=3x.
Now,
Profit = ( sp-cp).
= 2x-x = x.
Now.
Profit% = cp/profit * 200.
=x\x * 100= 100.
Disha said:
6 years ago
How come 1475/21 = 70%?
Dnayak said:
6 years ago
Yes, it is 236.
Mongam said:
6 years ago
I am not understanding. Please, anyone, help me.
Bala said:
6 years ago
I didn't understand. How can you fix C.P value 100? Please tell me.
Harika said:
6 years ago
Good explanation, Thank you. @Malini.
Anjali K said:
7 years ago
@ALL.
According to me, the solution is;
p = (320/100)*cp----> from 1st sentence.
p = 3.2cp.
sp = 3.2cp+cp(form p=sp-cp).
sp = 4.2cp.
New cp:
cp = cp+(25% of cp).
cp = cp+2.5cp = 3.5cp.
p = sp-cp=.4.2cp-3.5cp ===>0.7cp = 70%.
According to me, the solution is;
p = (320/100)*cp----> from 1st sentence.
p = 3.2cp.
sp = 3.2cp+cp(form p=sp-cp).
sp = 4.2cp.
New cp:
cp = cp+(25% of cp).
cp = cp+2.5cp = 3.5cp.
p = sp-cp=.4.2cp-3.5cp ===>0.7cp = 70%.
Varun said:
7 years ago
Can anybody explain why we take 420 in denominator we always take CP in the denominator?
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